[英]compare date stored in varchar in mysql
I am getting one issue, I am trying to fetch all records whose date is less than current date, but problem is date stored in 15-Nov-13
formate(in varchar(20)) 我收到一个问题,我正在尝试获取日期小于当前日期的所有记录,但问题是存储在
15-Nov-13
格式中的日期(在varchar(20)中)
now how to compare it? 现在该怎么比较呢?
I tried 我试过了
SELECT date_format( str_to_date( `ENDdatetime` , '%d/%M/%y' ) , '%Y%m' ) , `CLIENT_PROMO_ID`
FROM `tb_um_promo_schedule`
ORDER BY `CLIENT_PROMO_ID` DESC
LIMIT 0 , 30
but it returns NULL, 但它返回NULL,
so what to do here? 那怎么办?
The format you gave in your question ( 15-Nov-13
) does not match the format you are trying to convert in this: 您在问题中提供的格式(
15-Nov-13
)与您尝试转换的格式不符:
'%d/%M/%y'
Should it not be 不应该
'%d-%M-%y'
instead? 代替?
SELECT date_format( str_to_date( `ENDdatetime` , '%d-%M-%y' ) , '%Y%m' ) , `CLIENT_PROMO_ID`
FROM `tb_um_promo_schedule`
ORDER BY `CLIENT_PROMO_ID` DESC
LIMIT 0 , 30
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.