如何将char转换为ascii十进制值？

Question

I need to take a keyboard input letter, and save that letter's decimal value as an integer. How can I do that with scanf ?

Answer 1

I just figured out myself.

if I want to store the decimal value of 'z'

I can just do int value='z'-'a'+ 97

This is what I wanted to know.

Answer 2

This code reads a char from keyboard ( stdin ) using scanf() , stores it in byte-sized variable c of type char , and then prints its ASCII decimal value as an int to stdout :

char c;    
scanf("%c", &c);    
printf("%d", c);

Answer 3

If you want to output the ASCII value, simply printf() with the %d format string.

char ch = 'a';
printf("%d", a); // should be 97