MYSQL：WHERE NOT LIKE'％（SELECT column_name FROM table_name）％'

Question

i try to find %column_name% from another table_name i see the result but he seems to ignore the %% 我试图从另一个table_name中找到％column_name％我看到了结果，但他似乎忽略了%%

Why it does not work for me? 为什么它对我不起作用？

SELECT column_name FROM table_name WHERE NOT LIKE '%(SELECT column_name FROM table_name)%'

thanks, Apologies if I do not act according to the rules, this is my first question. 谢谢，道歉，如果我不遵守规则，这是我的第一个问题。

Answer 1

Try this: 尝试这个：

SELECT column_name FROM table_name WHERE NOT LIKE (SELECT CONCAT('%', column_name, '%') FROM table_name)

You can't just include a query in a string, so put the wildcards next to the column name in a query and return that to the NOT LIKE. 您不能只在字符串中包含查询，因此在查询中将通配符放在列名旁边，并将其返回到NOT LIKE。

Answer 2

SELECT column_name
FROM table_name T
WHERE NOT EXISTS ( SELECT column_name from other_table O
                   WHERE O.column_name LIKE CONCAT('%',T.column_name,'%')
                 )

MYSQL：WHERE NOT LIKE'％（SELECT column_name FROM table_name）％'

问题描述

2 个解决方案

解决方案1
2 已采纳 2014-04-06 07:59:15

解决方案2
0 2014-04-06 08:03:00

MYSQL：WHERE NOT LIKE&#39;％（SELECT column_name FROM table_name）％&#39;

问题描述

2 个解决方案

解决方案1 2 已采纳 2014-04-06 07:59:15

解决方案2 0 2014-04-06 08:03:00

MYSQL：WHERE NOT LIKE'％（SELECT column_name FROM table_name）％'

解决方案1
2 已采纳 2014-04-06 07:59:15

解决方案2
0 2014-04-06 08:03:00