如何结合两个不同的mySQL查询？

Question

I have tried to distinct make AND model like make, model

$result=mysql_query("SELECT distinct make, model FROM used order by make asc");

and afterwards

    <? while($row=mysql_fetch_array($result)) { ?>
    <option value=<?=$row['make']?>><?=$row['make']?></option>
    <? } ?>

and

 <? while($row=mysql_fetch_array($make)) { ?>
    <option value=<?=$row['model']?>><?=$row['model']?></option>
    <? } ?>

but I get only the model to be displayed, and not correct.

Now I am using

$make=mysql_query("SELECT distinct make FROM used order by make asc");
$model=mysql_query("SELECT distinct model FROM used order by model asc");

Is there a better way?

Answer 1

I suspect you are misunderstanding what is happening here:

while($row=mysql_fetch_array($result))

if you: var_dump($row) then you will see it has both columns in it. ie $row['make'] and $row['model'] with the values that you expect.

You need to process both columns at once.

I have no idea what this:

<? while($row=mysql_fetch_array($make)) { ?>
    <option value=<?=$row['model']?>><?=$row['model']?></option>
    <? } ?>

is doing but it cannot be helpful. It it safe to delete it.

I will not create tested code as the 'mysql_*' functions are depreciated in PHP.