[英]how to get message-id of email sent from smtplib
I want to record users reply to my mail and display it as thread in my application.我想记录用户对我邮件的回复并将其显示为我的应用程序中的线程。 For this purpose I am using help of message-id in present in the email head.
为此,我在 email 头中使用了 message-id 的帮助。 When I sent a mail I can see message-id being printed on the screen how do i get this message-id.
当我发送邮件时,我可以看到屏幕上正在打印消息 ID 我如何获取此消息 ID。 Also the message-id created by me is overrided.
我创建的消息 ID 也被覆盖。 my code is as below.
我的代码如下。
import smtplib
from email.mime.text import MIMEText
subject = 'Hello!'
message = 'hiii!!!'
email = 'someone@somewhere.com'
send_from = 'me@example.com'
msg = MIMEText(message, 'html', 'utf-8')
msg['Subject'] = subject
msg['From'] = send_from
msg['To'] = email
msg['Message-ID'] = '01234567890123456789abcdefghijklmnopqrstuvwxyz'
send_to = [email]
smtp_server = 'email-smtp.us-east-1.amazonaws.com'
smtp_port = 587
user_name = 'abcd'
password = 'abcd'
try:
server = smtplib.SMTP(smtp_server, smtp_port)
server.set_debuglevel(True)
server.starttls()
server.ehlo()
server.login(user_name,password)
server.sendmail(send_from, send_to, msg.as_string())
except Exception, e:
print e
使用email.utils.make_msgid
创建符合RFC 2822的Message-ID标头:
msg-id = [CFWS] "<" id-left "@" id-right ">" [CFWS]
I found the above answer to be incredibly confusing.我发现上面的答案令人难以置信的混乱。 Hopefully the below helps others:
希望以下内容对其他人有所帮助:
import smtplib
import email.message
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.base import MIMEBase
from email import encoders
import email.utils as utils
def send_html_email(subject, msg_text,
toaddrs=['foo@gmail.com']):
fromaddr = 'me@mydomain.com'
msg = "\r\n".join([
"From: " + fromaddr,
"To: " + ",".join(toaddrs),
"Subject: " + subject,
"",
msg_text
])
msg = email.message.Message()
msg['message-id'] = utils.make_msgid(domain='mydomain.com')
msg['Subject'] = subject
msg['From'] = fromaddr
msg['To'] = ",".join(toaddrs)
msg.add_header('Content-Type', 'text/html')
msg.set_payload(msg_text)
username = fromaddr
password = 'MyGreatPassword'
server = smtplib.SMTP('mail.mydomain.com',25)
#server.ehlo() <- not required for my domain.
server.starttls()
server.login(username, password)
server.sendmail(fromaddr, toaddrs, msg.as_string())
server.quit()
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