[英]Servlet doesn't execute response.sendRedirect(addressPath); , but does execute response.sendRedirect() without path
Consider the following hierarchy : 考虑以下层次结构:
When I send redirect like this : 当我这样发送重定向时:
response.sendRedirect("error404.jsp"); // no path here !!!
I reach the page error404.jsp
. 我到达页面
error404.jsp
。
But when I use a path : 但是当我使用路径时:
String addressPath = "/WEB-INF/results/admin/adminPage.jsp";
response.sendRedirect(addressPath); // with path !!!
I get 404 : 我得到404:
HTTP Status 404 -
type Status report
message
description The requested resource is not available.
Apache Tomcat/7.0.50
What am I doing wrong here ? 我在这里做错了什么?
Much appreciated ! 非常感激 !
This method can accept relative URLs;the servlet container must convert the relative URL to an absolute URL before sending the response to the client.
此方法可以接受相对URL; Servlet容器必须在将响应发送到客户端之前将相对URL转换为绝对URL。 If the location is relative without a leading '/' the container interprets it as relative to the current request URI.
如果位置是相对的而没有前导“ /”,则容器会将其解释为相对于当前请求URI的相对位置。 If the location is relative with a leading '/' the container interprets it as relative to the servlet container root.
如果位置与前导“ /”相对,则容器将其解释为相对于servlet容器根。 If the location is relative with two leading '/' the container interprets it as a network-path reference (see RFC 3986: Uniform Resource Identifier (URI): Generic Syntax, section 4.2 "Relative Reference").
如果位置与两个前导“ /”相对,则容器将其解释为网络路径引用(请参阅RFC 3986:统一资源标识符(URI):通用语法,第4.2节“相对引用”)。
Note that the argument is not a path within the servlet context like a RequestDispatcher
would use, it as a URL used in the Location
header of the 302 response. 请注意,该参数不是Servlet上下文中的路径(如
RequestDispatcher
所用),它是302响应的Location
标头中使用的URL。
So this 所以这
String addressPath = "/WEB-INF/results/admin/adminPage.jsp";
response.sendRedirect(addressPath); // with path !!!
will be transformed into a 302 response with the header 将被转换为带有标头的302响应
Location: http://whateverhost.com/WEB-INF/results/admin/adminPage.jsp
which you don't have a handler for, so 404. 您没有处理程序,所以是404。
On the other hand, this 另一方面,这
response.sendRedirect("error404.jsp"); // no path here !!!
becomes 变
Location: http://whateverhost.com/context-path/error404.jsp
Since error404.jsp
is outside WEB-INF
, it is accessible and therefore rendered by the JSP servlet and returned as a response. 由于
error404.jsp
在WEB-INF
外部,因此它是可访问的,因此由JSP servlet呈现并作为响应返回。
Because stuff under WEB-INF is not accessible to the client. 因为客户端无法访问WEB-INF下的内容。 Don't put your JSPs under WEB-INF if you want them to be accessible.
如果您希望JSP可以访问,则不要将它们放在WEB-INF下。
Alternatively, to make anything under WEB-INF accessible to the client, you would have to map it to a URL in web.xml: 或者,要使客户端可以访问WEB-INF下的任何内容,您必须将其映射到web.xml中的URL:
<servlet>
<servlet-name>adminPage</servlet-name>
<jsp-file>/WEB-INF/results/admin/adminPage.jsp</jsp-file>
</servlet>
<servlet-mapping>
<servlet-name>adminPage</servlet-name>
<url-pattern>/adminPage/*</url-pattern>
</servlet-mapping>
Then use the url-pattern you mapped: 然后使用您映射的url模式:
response.sendRedirect("./adminPage/");
Which is rather pointless. 这是毫无意义的。 You could achieve basically the same thing with your JSP outside of WEB-INF and using a URL Rewrite Filter.
使用WEB-INF之外的JSP并使用URL重写过滤器,您可以实现基本相同的操作。 In short, you probably have no real reason to put your JSPs under WEB-INF.
简而言之,您可能没有真正的理由将JSP置于WEB-INF下。
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