[英]Select highest and lowest date
I now have a query like this: 我现在有这样的查询:
SELECT DATE_FORMAT(`Datum`, '%e %M') AS `DATE`, tag AS `TAG`, value AS `VALUE`, addedTs as `addedTs`
FROM dailyMessage
INNER JOIN `psttodo-uit`
ON dailyMessage.Code = `psttodo-uit`.`Hostess Code`
WHERE Code = "010"
I know get a result like this: 我知道得到这样的结果:
DATE TAG VALUE addedTs
4 April calls 3 2014-04-04 20:32:39
4 April endTS 2014-04-04 22:40:55 2014-04-04 22:40:55
4 April kmstart 32 2014-04-04 18:34:37
4 April kmstop 34434334 2014-04-04 18:35:30
4 April startTS 2014-04-04 18:35:00 2014-04-04 18:35:00
4 April visits 6 2014-04-04 22:40:53
5 April endTS 2014-04-05 01:37:41 2014-04-05 01:37:41
5 April kmstart 30 2014-04-05 01:37:41
5 April startTS 2014-04-05 01:13:25 2014-04-05 01:13:25
5 April visits 1 2014-04-05 01:13:23
7 April authorizations 4 2014-04-07 22:34:37
7 April calls 9 2014-04-07 23:18:28
7 April endTS 2014-04-07 23:35:32 2014-04-07 23:35:32
7 April kmstart 42 2014-04-07 18:10:43
7 April kmstop 55 2014-04-07 19:37:42
7 April startTS 2014-04-07 10:45:18 2014-04-07 10:45:18
7 April visits 6 2014-04-07 23:35:31
8 April endTS 2014-04-08 11:24:28 2014-04-08 11:24:28
8 April startTS 2014-04-08 11:24:28 2014-04-08 11:24:28
Now I would also like to select highest date from the psttodo-uit table. 现在,我还要从psttodo-uit表中选择最高日期。 This is what I want to do:
这就是我想做的:
In the psttodo-uit
table there is a Hostess Code
( == Code in my WHERE clausule
). 在
psttodo-uit
表中,有一个Hostess Code
( == Code in my WHERE clausule
)。 There is also a afgewerkt tablet datum
field in the table of datetype datetime
. datetime
类型datetime
的表中还有一个afgewerkt tablet datum
字段。
The dates variate like so: 日期像这样变化:
2014-04-04 11:41:22
2014-04-03 17:20:01
2014-04-01 15:12:08
2014-04-07 22:20:47
2014-04-08 11:21:18
Now when I do a query I would like to select the max time of the specific day. 现在,当我进行查询时,我想选择特定日期的最长时间。 I tried it like this:
我这样尝试过:
SELECT DATE_FORMAT(`Datum`, '%e %M') AS `DATE`, tag AS `TAG`, value AS `VALUE`, addedTs as `addedTs`, MAX(`afgewerkt tablet datum`) AS `TimeSorE`
FROM dailyMessage
INNER JOIN `psttodo-uit`
ON dailyMessage.Code = `psttodo-uit`.`Hostess Code`
WHERE Code = "010"
But then I got this: 但是后来我得到了:
4 April calls 3 2014-04-04 20:32:39 2014-04-09 11:49:42
Two problems: 两个问题:
Is there someone who can help me with this? 有谁可以帮助我吗?
UPDATE: 更新:
What I've tried: 我尝试过的
SELECT DATE_FORMAT(`Datum`, '%e %M') AS `DATE`, tag AS `TAG`, value AS `VALUE`, addedTs as `addedTs`, MAX(`afgewerkt tablet datum`) AS `TimeSorE`
FROM dailyMessage
INNER JOIN `psttodo-uit`
ON dailyMessage.Code = `psttodo-uit`.`Hostess Code`
WHERE Code = "010"
GROUP BY DATE_FORMAT(`Datum`, '%e %M')
Gave me this: 给我这个:
4 April calls 3 2014-04-04 20:32:39 2014-04-09 15:46:04
5 April endTS 2014-04-05 01:37:41 2014-04-05 01:37:41 2014-04-09 15:46:04
7 April authorizations 4 2014-04-07 22:34:37 2014-04-09 15:46:04
8 April endTS 2014-04-08 11:24:28 2014-04-08 11:24:28 2014-04-09 15:46:04
But I need them all (with all tags). 但是我都需要它们(带有所有标签)。
SELECT DATE_FORMAT(`Datum`, '%e %M') AS `DATE`, GROUP_CONCAT(tag) AS `TAG`, value AS `VALUE`, addedTs as `addedTs`, MAX(`afgewerkt tablet datum`) AS `TimeSorE`
FROM dailyMessage
INNER JOIN `psttodo-uit`
ON dailyMessage.Code = `psttodo-uit`.`Hostess Code`
WHERE Code = "010"
GROUP BY DATE_FORMAT(`Datum`, '%e %M')
IF you need the result set as seperate rows try this 如果您需要将结果集作为单独的行,请尝试以下操作
SELECT A.DATE ,A.CODE,TAG,addedTs,TimeSorE
(
SELECT DATE_FORMAT(`Datum`, '%e %M') AS `DATE`,dailyMessage.Code AS CODE
MAX(`afgewerkt tablet datum`) AS `TimeSorE`
FROM dailyMessage
INNER JOIN `psttodo-uit`
ON dailyMessage.Code = `psttodo-uit`.`Hostess Code`
WHERE Code = "010"
GROUP BY DATE_FORMAT(`Datum`, '%e %M')
) A , dailyMessage B
WHERE
A.CODE = B.CODE AND
A.DATE = B. DATE_FORMAT(`Datum`, '%e %M')
This is absolutely works for me: 这绝对适合我:
SELECT
DATE_FORMAT(`Date`, '%e %M') AS `DATE`,
tag AS `TAG`,
value AS `VALUE`,
addedTs as `addedTs`,
MAX(`afgewerkttabletdatum`) AS `TimeSorE`
FROM Test
GROUP BY DATE_FORMAT(`Date`, '%e %M')
Here is an example: 这是一个例子:
I think this gonna work: 我认为这会起作用:
SELECT DATE_FORMAT(`Datum`, '%e %M') AS `DATE`,
tag AS `TAG`,
value AS `VALUE`,
addedTs AS `addedTs`,
t2.`TimeSorE`
FROM dailyMessage
INNER JOIN (SELECT `Hostess Code`,
MAX(`afgewerkt tablet datum`) AS `TimeSorE`
FROM `psttodo-uit`
GROUP BY `Hostess Code`) t2 ON dailyMessage.Code = t2.`Hostess Code`
WHERE Code = "010"
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