Beautifulsoup：稀烂的xml，单循环遍历每个项目

Question

Say you have some XML that is structured like this but could take any shape using these tag with the same tag names deeper and may be reused in weird ways:

<a>
    <b>
        <c />
    </b>
    <b>
        <c />
    </b>
    <b>
        <b>
            <d>
                <b>
                    <e>
                        <f>
                            <c />
                        </f>
                    </e>
                </b>
                <b>
                    <e>
                        <f>
                            <c />
                        </f>
                    </e>
                </b>
            </d>
        </b>
    </b>
    <b>
        <b>
            <c />
        </b>
    </b>
</a>

I want to make it go through each of the tags one by one in the order they appear from top to bottom the repeated tags can be used in any order or structure. I want to go through each tag one by one using beautifulsoup. for example:

soup = BeautifulSoup(xmlcode, "xml")
for asd in soup.findAll(True, recursive=False):
    print asd.prettify()
    print "---------"

All this returns is a single large bs4.element.Tag. I would want it to return 19 lines instead in the order that they appear. Basically all I want to do is go over each single tag using hopefully a single loop or as few loops as possible. Im open to better options than beautifulsoup if possible.

Answer 1

You are looking for .children :

xml_soup = BeautifulSoup(xml, "xml")
for tag in xml_soup.children:
    print tag