如何获得Linux内核的时间戳？

Question

int netif_rx(struct sk_buff *skb) 
{
if(skb -> stamp.tv_sec ==0)
do_gettimeofday(&skb->stamp);
}

the above api is the receiver side api, which receives the data from the sender. I want to calculate t he time when it receives the data and store it in a buffer. the above api at line number 2993 is available in kernel source code at: /linux/net/core/dev.c
but I am getting ERROR: as struct sk_buff has no member named stamp.

http://lxr.free-electrons.com/source/include/linux/skbuff.h Could someone please help me : how to get the timestamp for linux kernel.

Later I changed my code to :

 int netif_rx(struct sk_buff *skb) 
    {
    if(skb -> tstamp.off_sec ==0)
    do_gettimeofday(&skb->tstamp);
    }

now I am getting error as : ktime_t has no memeber named "tv_sec". struct timeval but argument is of type unio ktime_t.

Answer 1

sk_buff->tstamp is variable of ktime_t type. do_gettimeofday sets time to variable of struct timeval . You have different types here and so you need a conversion. A simple one would be:

int netif_rx(struct sk_buff *skb) 
{
    if(skb -> tstamp.off_sec ==0)
    {
        struct timespec now;
        getnstimeofday(&now);
        skb->tstamp = timespec_to_ktime(now);
    }
}

Answer 2

尝试使用tstamp代替stamp 。