遍历DOM从单击的元素获取节点

Question

OK, what I'm trying to do is the following, when I click on any element on the page and I want to build up a tree of the DOM of where the element lives. 好的，当我单击页面上的任何元素时，我想做的事情如下：我想为元素所在的DOM构建一棵树。

example of the html html的例子

<html>
  <head>
  </head>
  <body>
    <ul>
     <li><span>Elem 1</span></li>
     <li><span>Elem 2</span></li>
     <li><span>Elem 3</span></li>
    </ul>
  </body>
</html>

This is the JS (comes from an click event and passes through the clicked element) 这是JS（来自click事件，并通过clicked元素传递）

function getElementIdentifier(elem, domSelector, firstId) {
    if(elem.tagName === 'HTML') {
        return 'HTML ' + domSelector;
    } else {
        return getElementIdentifier(elem.parentNode, ' > ' +elem.tagName + ' ' + domSelector, firstId);
    }
}

which works to an extent but when it comes to the fact that I've clicked on the third item in the list it only retrieves the following: 这在一定程度上有效，但是当我单击列表中的第三项时，它只会检索以下内容：

HTML  > BODY  > UL  > LI  > SPAN

But I want to retrieve the 3rd as this is the one I clicked. 但是我想检索第三个，因为这是我单击的那个。 I've got a codepen I did to show. 我有一个Codepen可以显示。

http://codepen.io/tom-maton/pen/FljpL/ http://codepen.io/tom-maton/pen/FljpL/

I'm not wanting to use jQuery - just looking to use raw js. 我不想使用jQuery-只是想使用原始js。

Answer 1

This is the fastest way to do it (at least for me) 这是最快的方法（至少对我而言）

function clickHandler(event) {
    var target = event.target,
    breadcrumb = [];

    while (target) {
        breadcrumb.unshift(target.tagName);
        target = target.parentElement;
    }
    console.log(breadcrumb.join(" > "));
}

document.addEventListener('click', clickHandler, false);

Fiddle here: http://jsfiddle.net/NTEv2/ 在这里提琴： http : //jsfiddle.net/NTEv2/

Version with siblings: 有兄弟姐妹的版本：

function getTagName(element) {
    return element.tagName;
}
function clickHandler(event) {
    var target = event.target,
        breadcrumb = [],
        temp;

    while (target) {
        target = target.parentElement;
        if (target) {
            breadcrumb.unshift(([].slice.call(target.children).map(getTagName).join(" + ")));
        }
    }

    // HTML is always there
    breadcrumb.unshift(document.documentElement.tagName);

    console.log(breadcrumb.join(" > "));
}

document.addEventListener('click', clickHandler, false);

Fiddle here: http://jsfiddle.net/NTEv2/1/ 在这里提琴： http : //jsfiddle.net/NTEv2/1/

Version with only previous siblings (as requested): 仅具有先前同级的版本（根据要求）：

function clickHandler(event) {
    var target = event.target,
        breadcrumb = [],
        part = [],
        prev = target,
        temp;

    while (target) {
        if (prev) {
            part.unshift(prev.tagName);
            prev = prev.previousElementSibling;
        } else {
            target = target.parentElement;
            prev = target;
            breadcrumb.unshift(part.join(" + "));
            part = [];
        }
    }

    console.log(breadcrumb.join(" > "));
}

document.addEventListener('click', clickHandler, false);

Fiddle here: http://jsfiddle.net/NTEv2/11/ 在这里提琴： http : //jsfiddle.net/NTEv2/11/

遍历DOM从单击的元素获取节点

问题描述

1 个解决方案

解决方案1
2 已采纳 2014-04-10 21:08:36

遍历DOM从单击的元素获取节点

问题描述

1 个解决方案

解决方案1 2 已采纳 2014-04-10 21:08:36

解决方案1
2 已采纳 2014-04-10 21:08:36