[英]Negative lookbehind regex in Javascript
I want to match all strings that start with an @ unless they have other characters in front of the @ as well. 我想匹配所有以@开头的字符串,除非它们在@前面也有其他字符。 Simple example: in
@one @two and bla@three
I want to match @one
and @two
but not @three
. 简单的例子:在
@one @two and bla@three
我想匹配@one
和@two
但不匹配@three
。 It's for highlighting usernames in a chatroom. 用于突出显示聊天室中的用户名。
These strings can be anywhere in a sentence (right at the start or in the middle). 这些字符串可以在句子中的任何位置(在开头或中间)。
I actually thought that (?![a-zA-Z])@[a-zA-Z]+
should work but it still matches @three
too. 我实际上认为
(?![a-zA-Z])@[a-zA-Z]+
应该可以,但是它仍然也匹配@three
。
You don't need a regex look around, you can use a simple regex like this: 您不需要查看正则表达式,可以使用如下所示的简单正则表达式:
\B@\w+
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