通过href传递变量？

Question

I've read a few resources and figured out the gist of doing this, but I'm having a hard time with it.

I want to pass a var to '<a href="documents/edit">' so I tried
'<a href="documents/edit?var=<?php echo $this->request->post("doc_id")?>">' ,
but it breaks my site. I don't really know what I'm doing so could someone let me know if I did something wrong?

This is all taking place within an html file, fyi.

Edit: Another thing about this is that I'm using Kendo and PHPixie.

Answer 1

Well, actually in PHPixie you cannot use $this->request in your views because $this doesn't represent the Controller (in which you can find the variable $request) but the View !

The best way to pass the $_POST to your view is by doing this :

public function action_myFunction()
{
    $this->view->post = $this->request->post();
    $this->view->subview = 'myView';
}

And in your view, you can do

<div>
    <?=$post['doc_id'];?>
</div>

You can find more info on this blog : http://phpixie.jeromepasquier.com/accessing-variables-view/

By the way, it is good practice to always prepend your href and src with a starting slash. Why ? Because if you are on http://example.com/exa/mple and you want to go to http://example.com/doc_id you will need to tell the browser that you start the url from the host. Otherwise without a starting slash, you will end up on http://example.com/exa/doc_id .

Answer 2

After searching the code I have, I found that this is the correct way to do things:

<a href="<?php echo $exepath; ?>documents/edit?doc_id=document_id"></a>

Hopefully, this will help out anyone using PHPixie or Kendo in the future.

Answer 3

Views should not access POST directly. Ever.

Passing the POST to your view will work for sure, but violates the main concept of the MVC.

Doing this:

<?=$post['doc_id'];?>

Will throw an error if the POST var "doc_id" is not present in the $post array because there is no error checking and PHPixie works in strict mode.

The BEST way to assign a variable that will be used later on the view like this:

public function action_myFunction()
{
    $this->view->doc_id = $this->request->post('doc_id');  //will return NULL if not present, checking logic should be done before if needed
    $this->view->subview = 'myView';
}

And in your view:

<div>
    <?= $doc_id ?>
</div>