JSON解码和字符串问题

Question

having a bit of an issue here. I'm passing data over an AJAX command to my php script. The data travels across fine.

Print_r

Array 
( [0] => stdClass Object 
    ( [Loc] => Main Door 
      [Module] => O2 
      [Dect] => O2 
      [GasDec] => O2 
      [ScB4] => 
      [ScA4] => 
      [A1] => 
      [A2] => 
      [CalGas] => 
      [CalGasA] => 
      [Factor] => 
      [ZB4] => 
      [ZA4] => 
      [CalB4] => 
      [CalA4] => 
      [CHNoID] => 5 
      [JobID] => 3 )
)

I can use The following method just fine but when i use option two it doesn't like it due to this error message:

Catchable fatal error: Object of class stdClass could not be converted to string

Methods

//Method one
echo "JobID: " . $comm[0]->JobID; // result: 3
//Method two
echo "JobID: '$comm[0]->JobID'"; // get error message

The reason im using method two is so I can pass the information into mysql. If anyone knows something i'm missing or it can't be done or even a easier way. please say.

Thanks.

EDIT

Query

$sql = "INSERT INTO
  calinfo (Sbefore, Safter, A1, A2, CalGas, Factor, Zbefore, Zafter, Cbefore, Cafter, SysInfoID)
  VALUES
  ('$comm[$i]->ScB4', '$comm[$i]->ScA4', '$comm[$i]->A1', '$comm[$i]->A2', '$comm[$i]->CalGasA', '$comm[$i]->Factor', '$comm[$i]->ZB4', '$comm[$i]->ZA4', '$comm[$i]->CalB4', '$comm[$i]->CalA4', '$comm[$i]->CHNoID');";

  $sql .= "UPDATE
  jobs
  SET
  CompletedBy = $tech
  WHERE JobID = '$comm[$i]->JobID';"; //<-- when i try the method of "WHERE JobID = ".$comm[$i]->JobID.";"; it doesnt like it...

Answer 1

You may need to do as

echo "JobID: '{$comm[0]->JobID}'"; 

So in the query u can use it as where some_col = '{$comm[0]->JobID}'

Answer 2

Try like this

$sql .= "UPDATE
jobs
SET
CompletedBy = $tech
WHERE JobID = '".$comm[$i]->JobID."'";

Answer 3

As the error message saies, the return cannot be converted to fit into a string directly.

echo sprintf( "JobID: '%s'",$comm[0]->JobID);

or

echo "JobID: '{$comm[0]->JobID}'"; 

or

echo "JobID: '" . $comm[0]->JobID . "'";

should do the trick

Answer 4

Simple double quotes won't interpolate complex combinations like this. You need to use curly braces to achieve this, eg echo "JobID: {$comm[0]->JobID}"; .

You could however also use printf , eg printf("JobID: %s", $comm[0]->JobID); .