你能告诉我这个 PHP 表单有什么问题吗？
[英]Can you tell me what's wrong with this PHP form?
问题描述
I'm trying to make a simple website in which I ask the user for their name and DOB in order to output "Hello (name) you are (age) years old and you will graduate in (Graduation Date). I feel like my code is right but when i submit the form it leads me to a blank page.
我正在尝试制作一个简单的网站，在该网站中我询问用户他们的姓名和出生日期，以便输出“你好（姓名）你是（年龄）岁，你将毕业（毕业日期）。我觉得我的代码是正确的，但是当我提交表单时，它会将我带到一个空白页面。
My code: HTML我的代码： HTML
<body>
<center>
<form action="aform.php" method="post">
Name:<input type="text" name="name" />
<br />
Date of Birth:
<input type="text" size="4" placeholder="mm" name="month" />
<input type="text" size="4" placeholder="dd" name="day" />
<input type="text" size="6" placeholder="yyyy" name="year" />
<input type="submit" name="submit" value="Submit" />
<br />
</form>
</center>
</body>
PHP: PHP：
<?php
if($_POST["submit"]){
$name = $_POST["name"];
$day = $_POST["day"];
$month = $_POST["month"];
$year = $_POST["year"];
$datedisplay = date("yyyy");
$birth = array($day,$month,$year);
if($name = $year = $month = $day = ""){
echo "You must fill out everything!";
} else if($year = $month = $day > 0) {
$yourage = 2014 - $year;
$gradyear = $year + 22;
$graddate = "6/TBA/$gradyear";
echo "Hello" . $name . ", you are" . $yourage . "years old and you will graduate from college in" . $graddate ;
}
}
?>
Sorry if I presented this wrong I'm new to this website.对不起，如果我提出这个错误，我是这个网站的新手。
5 个解决方案
解决方案1
1 已采纳 2014-04-11 15:26:45
your tests are wrong.你的测试是错误的。 Here is a corrected code:这是一个更正的代码：
<?php
if($_POST["submit"]) {
$name = $_POST["name"];
$day = $_POST["day"];
$month = $_POST["month"];
$year = $_POST["year"];
$datedisplay = date("yyyy");
$birth = array($day,$month,$year);
if(empty($name) || empty($year) || empty($month) || empty($day)) {
echo "You must fill out everything!";
} else if($year > 0 && $month > 0 && $day > 0) {
$yourage = 2014 - $year;
$gradyear = $year + 22;
$graddate = "6/TBA/$gradyear";
echo "Hello" . $name . ", you are" . $yourage . "years old and you will graduate from college in" . $graddate ;
}
}
?>
解决方案2
0 2014-04-11 15:23:51
I think我认为
if($name = $year = $month = $day = ""){
echo "You must fill out everything!";
}
that is not working very well.这不是很好。 You should check every variable with empty or isset .您应该检查每个变量为empty或isset 。 With one = you give the variable a value in your case nothing.使用 one =在你的情况下，你给变量一个值。
if(!empty($name) && !empty($year) && !empty($month)) {
解决方案3
0 2014-04-11 15:24:42
1) you need to use == in ifs ... a single = works differently 1) 你需要在 ifs 中使用 == ......单个 = 的工作方式不同
( this way, you just try to check, if you can assign the value of $year to $name ) （这样，您只需尝试检查，是否可以将 $year 的值分配给 $name ）
if($name = $year = $month = $day = "")
2) you need to rewrite that if 2）你需要重写，如果
if( ( strlen( $name ) == 0 ) && ( strlen( $year ) == 0 ) .....
3) yo need to rewrite your elseif stuff as well 3）你也需要重写你的elseif东西
解决方案4
-1 2014-04-11 15:22:01
Try this:尝试这个：
<?php
if($_SERVER['REQUEST_METHOD'] == 'POST'){
$name = $_POST["name"];
$day = $_POST["day"];
$month = $_POST["month"];
$year = $_POST["year"];
$datedisplay = date("yyyy");
$birth = array($day,$month,$year);
if($name == "" || $year == "" || $month == "" || $day == ""){
echo "You must fill out everything!";
}
else if($year > 0 && $month > 0 && $day > 0){
$yourage = 2014 - $year;
$gradyear = $year + 22;
$graddate = "6/TBA/$gradyear";
echo "Hello" . $name . ", you are" . $yourage . "years old and you will graduate from college in" . $graddate ;
}
}
?>
if this does not work, edit your question and add the HTML form code that you have written如果这不起作用，请编辑您的问题并添加您编写的 HTML 表单代码
解决方案5
-1 2014-04-11 15:27:49
do not use assign operator instead of compression operator.不要使用赋值运算符代替压缩运算符。 in php在 php 中
if($name = $year = $month = $day = ""){
}
else if($year = $month = $day > 0){}
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