更改bash脚本中的时间输出

Question

How to change this time output ?

date --date="@$(echo $(TZ=UTC date +%s) - $(date +%s)'%(5*60)-(5*60)' | bc)"

Output: za apr 12 00:25:00 CEST 2014

Should output in this layout: %Y%m%d%H%M

How to implement this in the string ?

Thanks!!

Answer 1

i think this should do what you want:

d="@$(echo $(TZ=UTC date +%s) - $(date +%s)'%(5*60)-(5*60)' | bc)"&&echo `date --date="$d"` `date --date="$d" +%Y%m%d%H%M`

d="@$(echo $(TZ=UTC date +%s) - $(date +%s)'%(5*60)-(5*60)' | bc)"&&echo `date --date="$d" --utc` `date --date="$d" +%Y%m%d%H%M --utc`

Second one is in UTC.