如何通过ajax调用从上一页发送的php页面中获取变量

Question

I am making an ajax call from one php page to second.in which im sending three variables. But im not able to get it in next php page where im sending them ... please check. Index.php

function loadMoreData(offset){
var part1= "<?php echo ($part1);?>"; 

var part2="<?php echo ($part2);?>";

    $.ajax({
        type: 'get',
        async:false,
        url: 'getMoreData.php',
        data:{offset:offset,part1:part1,part2:part2},
        success: function(data){

            $(data).appendTo("#product");
        },
        error: function(data){
            alert("ajax error occured…"+data);
        }
    }).done(function(){
        $(window).bind("scroll",function(){
        scrollMore();   
    });
    });
}


});

getMoredata.php

 <?php
    include('connection.php');

    $offset = (isset($_REQUEST['offset']) && $_REQUEST['offset']!='') ? $_REQUEST['offset'] : '';
    $limit = 10;
    $var1 = (isset($_REQUEST['part1']) && $_REQUEST['part1']!='') ? $_REQUEST['part1'] : '';

    $var2 = (isset($_REQUEST['part2']) && $_REQUEST['part2']!='') ? $_REQUEST['part2'] : '';

    $qry1 = mysql_query('select * from xml WHERE  PNAME LIKE  \'%$var2\' AND CATEGORY like \'%$var1\' limit ".$offset.", ".$limit."');
    print $qry1;
    ?>

I m able to send the three variables from index.php page but im not able to get them in getMoreData.php,due to which im not able to run the sql command...

Please verify guys....

Answer 1

尝试所有变量

$offset = isset($_GET['offset']) ? $_GET['offset'] : $_POST['offset'];

Answer 2

Use $_GET instead of $_REQUEST .

Also you are not sending the rows properly, use-

print_r(mysql_fetch_array($qry1));

Then try to check the response in browser's console with - console.log(data) and then manipulate it accordingly.