[英]Verifying a Text in SWT and trying to clear it but doesn't work
I am trying to verify a text in SWT to allow only binary numbers and it works, but my problem is that I have a button that I need to reset the field but it doesn't work. 我正在尝试验证SWT中的文本以仅允许二进制数字,并且它可以工作,但是我的问题是我有一个按钮需要重置该字段,但它不起作用。
Here is the code 这是代码
DACMUX.addVerifyListener(new VerifyListener() {
public void verifyText(VerifyEvent e) {
e.doit = false;
char myChar = e.character;
if (myChar == '1' || myChar == '0' || myChar == '\b'){
e.doit = true;
}
}
});
reset.addSelectionListener(new SelectionListener() {
@Override
public void widgetSelected(SelectionEvent e) {
DACMUX.setText("");
}
@Override
public void widgetDefaultSelected(SelectionEvent e) {
// TODO Auto-generated method stub
}
});
Interesting case you got there. 有趣的情况,你到了那里。 Took me a while to figure it out. 花了我一段时间才能弄清楚。
Right, so here goes: The VerifyListener
is fired after you call setText("")
. 没错,这里是这样:在调用setText("")
之后,将触发VerifyListener
。 It checks your condition and it validates to false
, so nothing changes. 它检查您的状况,并验证为false
,因此什么都不会改变。
To make it work, you need to add one additional OR case to your if
, which checks if Event#text
equals ""
. 为了使其工作,您需要在if
添加一个额外的OR大小写,以检查Event#text
等于""
。 This is the case when you call setText("")
. 调用setText("")
时就是这种情况。 It won't mess up you other logic. 它不会弄乱您其他逻辑。
So here is the working if
: 所以这是工作的情况, if
:
if (myChar == '1' || myChar == '0' || myChar == '\b' || e.text.equals(""))
{
e.doit = true;
}
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