使用C代码从文件读取字符

Question

I have written a C code to count no of characters, words and lines in a file.
The code is as follows.

#include "stdio.h"
#include "conio.h"

#define FILE_NAME "abc.txt"

void main()
{
    FILE *fr;
    int noc = 0;
    int now = 0;
    int nol = 0;
    char ch;

    printf("hello world\n");
    getch();

    //clrscr();

    fr = fopen("..\\abc.txt","r");

    if(fr == NULL)
    {
        printf("\n error \n");
        getch();
        return;
    }

    ch = fgetc(fr);
    while(ch != EOF)
    {
        printf("%c", ch);
        noc++;
        if(ch == ' ');
        {
            now++;
        }
        if(ch=='\n')
        {
            nol++;
            now++;
        }
        ch=fgetc(fr);
    }

    fclose(fr);

    printf("\n noc = %d now = %d nol = %d\n", noc, now, nol);
    getch();
}

My file abc.txt is as follows.

Hello my friend. 
How are you doing? 

I am getting following output:

hello world
Hello my friend.
How are you doing?

 noc = 38 now = 40 nol = 2

The code is able to read no of characters and no of lines properly. However, it considers each character as a word. I am not understanding where am I going wrong when counting no of words in the code above.

Detailed explanations would be appreciated.
Thanks in advance.

Answer 1

if(ch == ' '); <------- see this (remove semicolon)
{
     now++;
}