[英]Project Euler 17 using Python
I'm currently solving Project Euler's problem number 17 using Python. 我目前正在使用Python解决Euler项目的问题编号17。 Here's the link for the problem statement:
这是问题陈述的链接:
http://projecteuler.net/problem=17 http://projecteuler.net/problem=17
Here's my solution in Python: 这是我在Python中的解决方案:
def no_to_words(n):
num = str(n)
s = ""
hunds = n/100
ten = n%100
tens = ten/10
units = ten%10
if(len(num) == 3):
if(n == 100):
return "one hundred"
if(hunds == 1):
s = s + "one hundred and"
elif(hunds == 2):
s = s + "two hundred and"
elif(hunds == 3):
s = s + "three hundred and"
elif(hunds == 4):
s = s + "four hundred and"
elif(hunds == 5):
s = s + "five hundred and"
elif(hunds == 6):
s = s + "six hundred and"
elif(hunds == 7):
s = s + "seven hundred and"
elif(hunds == 8):
s = s + "eight hundred and"
else:
s = s + "nine hundred and"
if(ten == 11):
s = s + " eleven"
return s
elif(ten == 12):
s = s + " twelve"
return s
elif(ten == 13):
s = s + " thirteen"
return s
elif(ten == 14):
s = s + " fourteen"
return s
elif(ten == 15):
s = s + " fifteen"
return s
elif(ten == 16):
s = s + " sixteen"
return s
elif(ten == 17):
s = s + " seventeen"
return s
elif(ten == 18):
s = s + " eighteen"
return s
elif(ten == 19):
s = s + " nineteen"
return s
if(tens == 2):
s = s + " twenty"
elif(tens == 3):
s = s + " thirty"
elif(tens == 4):
s = s + " forty"
elif(tens == 5):
s = s + " fifty"
elif(tens == 6):
s = s + " sixty"
elif(tens == 7):
s = s + " seventy"
elif(tens == 8):
s = s + " eighty"
elif(tens == 9):
s = s + " ninety"
if(units == 1):
s = s + " one"
elif(units == 2):
s = s + " two"
elif(units == 3):
s = s + " three"
elif(units == 4):
s = s + " four"
elif(units == 5):
s = s + " five"
elif(units == 6):
s = s + " six"
elif(units == 7):
s = s + " seven"
elif(units == 8):
s = s + " eight"
elif(units == 9):
s = s + " nine"
if(len(num) == 2):
if(n == 10):
return "ten"
if(ten == 11):
s = s + "eleven"
return s
elif(ten == 12):
s = s + "twelve"
return s
elif(ten == 13):
s = s + "thirteen"
return s
elif(ten == 14):
s = s + "fourteen"
return s
elif(ten == 15):
s = s + "fifteen"
return s
elif(ten == 16):
s = s + "sixteen"
return s
elif(ten == 17):
s = s + "seventeen"
return s
elif(ten == 18):
s = s + "eighteen"
return s
elif(ten == 19):
s = s + "nineteen"
return s
if(tens == 2):
s = s + "twenty"
elif(tens == 3):
s = s + "thirty"
elif(tens == 4):
s = s + "forty"
elif(tens == 5):
s = s + "fifty"
elif(tens == 6):
s = s + "sixty"
elif(tens == 7):
s = s + "seventy"
elif(tens == 8):
s = s + "eighty"
elif(tens == 9):
s = s + "ninety"
if(units == 1):
s = s + " one"
elif(units == 2):
s = s + " two"
elif(units == 3):
s = s + " three"
elif(units == 4):
s = s + " four"
elif(units == 5):
s = s + " five"
elif(units == 6):
s = s + " six"
elif(units == 7):
s = s + " seven"
elif(units == 8):
s = s + " eight"
elif(units == 9):
s = s + " nine"
if(len(num) == 1):
if(units == 1):
s = "one"
elif(units == 2):
s = "two"
elif(units == 3):
s = "three"
elif(units == 4):
s = "four"
elif(units == 5):
s = "five"
elif(units == 6):
s = "six"
elif(units == 7):
s = "seven"
elif(units == 8):
s = "eight"
elif(units == 9):
s = "nine"
if(len(num) == 4):
return "one thousand"
return s
final = ""
for e in range(1, 1001):
s = no_to_words(e)
final = final + s
ultimate = final.replace(" ", "")
print len(ultimate)
Now, the answer for this problem is (spoiler): 现在,这个问题的答案是(破坏者):
21124
21124
whereas, I'm getting 21121 as my answer. 而我的回答是21121。 What's wrong with my code?
我的代码有什么问题? I can't seem to figure out the problem.
我似乎无法找出问题所在。
You never covered the case where tens==1
. 您从未涉及过
tens==1
的情况。 And you don't consider exact multiples of 100. 而且您不考虑100的确切倍数。
It seems like you might be re-inventing the wheel a little bit here. 似乎您可能在这里重新发明了轮子。 Instead of using no_to_words I used the num2words library.
我没有使用no_to_words,而是使用了num2words库。 That seemed to give me the right answer.
那似乎给了我正确的答案。
total = 0
for num in range(1, 1001):
total += len(num2words(num).replace(" ", "").replace("-", ""))
print(total)
21124
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