将逗号分隔的字符串分配给元组数组-python，numpy

Question

Some shell escape command gives me:

a=!ls /cygdrive/s | grep "^Something6" | tr -d [A-Za-z] | sed "s/_.*$//" | sed "s/-/ /" | sed "s/ /,/"

['64,2014-04-01', '64,2014-04-02', '64,2014-04-03', '64,2014-04-04', '64,2014-04-07', '64,2014-04-07', '64,2014-04-08', '64,2014-04-09', '64,2014-04-11', '64,2014-04-14']

The final goal is to put this into a database with the columns version and date . For intermediate experimenting I would like to put the array of strings into an array of tuples or into a dictionary without much copying around.

Like:

version = np.empty(1,dtype=object_)
date = np.empty(1,dtype=object_)
version = a[1:]

But I need to split the string at the ','. How can this be achieved most elegantly with one gulp?

The result should be something like:

(('64','2014-04-01'),
 ('64','2014-04-02'),
     etc.
     ...

Answer 1

[tuple(x.split(',')) for x in a]