将JSON嵌套对象解析为String

Question

I have JSON object and I don't want to parse some of nested objects. Instead I want them as String (I have my reasons). Is there an easy way to do it? I've tried to implement custom Deserializer but I found it complicated in different ways (I don't want to concatenate tokens I just need whole object. It also doesn't consider ':' as token so it need special handling) or maybe I'm missing smth. Also putting quotes in json is not an option. I need that json the way it is.

JSON example:

{
   "lastName":"Bitman",
   "jsonObjectIDontWantToParse":{
      "somefield":1234
   }
}

Java object I want to parse json to.

 public class Jack {

        public String lastName;
        public String jsonObjectIDontWantToParse;

        @Override
        public String toString() {
            return "lastName=" + lastName + ", jsonObjectIDontWantToParse=" + jsonObjectIDontWantToParse;
        }

    }

Here's my main class

 public static void main(String[] args) throws IOException {

    ObjectMapper mapper = new ObjectMapper();
    final String jackString = "{\"lastName\":\"Bitman\",\"jsonObjectIDontWantToParse\":{\"somefield\":1234}}";
    Jack user = mapper.readValue(jackString, Jack.class);
    System.out.println(user);

}

I expect output to be like this

lastName=Bitman, jsonObjectIDontWantToParse={"somefield":1234}

---

Updated: So basically this is example what I'm looking for (except There are no such method). I want to skip any parsing for that node...

public class LeaveAsStringDeserializer extends JsonDeserializer<String> {

    @Override
    public String deserialize(JsonParser jp, DeserializationContext ctxt) throws IOException {
        return jp.getWholeObject().toString();
    }
}

Answer 1

I think, that you should use JsonNode class as a type of jsonObjectIDontWantToParse property:

class Jack {

    private String lastName;
    private JsonNode jsonObjectIDontWantToParse;

    // getters, setters, toString, other

    public String getJsonObjectIDontWantToParseAsString() {
        return jsonObjectIDontWantToParse.toString();
    }
}

You can add one additional method getJsonObjectIDontWantToParseAsString if you want to get String representation.

Example usage:

ObjectMapper mapper = new ObjectMapper();
Jack jack = mapper.readValue(json, Jack.class);
System.out.println(jack);
System.out.println(jack.getJsonObjectIDontWantToParseAsString());

Above program prints:

lastName=Bitman, jsonObjectIDontWantToParse={"somefield":1234}
{"somefield":1234}

Answer 2

To get to this:

lastName=Bitman, jsonObjectIDontWantToParse={"somefield":1234}

You just need to escape the String representation of jsonObjectIDontWantToParse . That means change it read:

jsonObjectIDontWantToParse: "{ \"somefield\": 1234 }"