Java正则表达式单词不以点结尾

Question

I need to print the simple bind variable names in the SQL query. I need to print the words starting with : character But NOT ending with dot . character. in this sample I need to print pOrg , pBusinessId but NOT the parameter . The regular expression ="(:)(\\\\w+)^\\\\." is not working.

Could you help in correcting the regular expression.

Thanks Peddi

public void testMethod(){ 
String regEx="(:)(\\w+)([^\\.])";  
String input= "(origin_table like 'I%' or (origin_table like 'S%' and        process_status =5))and header_id = NVL( :parameter.number1:NULL, header_id) and (orginization = :pOrg) and (businsess_unit = :pBusinessId";
Pattern pattern;
Matcher matcher;

    pattern = Pattern.compile(regEx);
    matcher = pattern.matcher(input);

    String grp = null;

    while(matcher.find()){

        grp = matcher.group(2);
        System.out.println(grp);

    }
}

Answer 1

You can try with something like

String regEx = "(:)(\\w+)\\b(?![.])";

• (:)(\\\\w+)\\\\b will make sure that you are matching only entire words starting with :
• (?![.]) is look behind mechanism which makes sure that after found word there is no .

This regex will also allow :NULL so if there is some reason why it shouldn't be matched share it with us.

---

Anyway to exclude NULL from results you can use

String regEx = "(:)(\\w+)\\b(?![.])(?<!:NULL)";

To make regex case insensitive so NULL could also match null compile this pattern with Pattern.CASE_INSENSITIVE flag like

Pattern pattern = Pattern.compile(regEx,Pattern.CASE_INSENSITIVE);

Answer 2

You can try:

Pattern regex = Pattern.compile("^:.*?[^.]$");

Demo

Answer 3

Since it looks like you're using camelcase, you can actually simplify things a bit when it comes to excluding :NULL :

:([az][\\\\w]+)\\\\b(?!\\\\.)

And $1 will return your variable names.

Alternative that doesn't rely on negative lookahead:

:([az][\\\\w]+)\\\\b(?:[^\\\\.]|$)