正则表达式将字母数字与特殊字符匹配

Question

I am trying to form an url in Django url pattern .

   url(r'^reports/(?P<bu>\w+|\W)/$', \
                LrsReportView.as_view(), name="elearning.lrsreports.region"),  

The bu can be a string or string alphanumeric or alphanumeric with special character (except /)

But the above url is showing error for

NoReverseMatch: Reverse for 'elearning.lrsreports.region' with arguments '(u'Lawn&Garden',)' and keyword arguments '{}' not found.

From the error I understood is this regex is not accepting the string having special character

Please help me out what might wrong here .

Answer 1

Your current RegEx will match:

• A string of one or more letters, numbers and/or underscores: [A-Za-z0-9_]+

OR

• A SINGLE character that is NOT a letter, number or underscore. [^A-Za-z0-9_]

You probably need something more like:

(?P<bu>[\w-]+)

This will match letters, numbers, underscore and hyphens. Add any other special characters you want as well (inside the square brackets). Remeber certain characters need escaping with \\ before them.

Answer 2

Try this-

/^(?=. [az])(?=. [AZ])(?=. \\d)(?=. (_|[^\\w])).+$/