来自bash脚本的.bashrc源

Question

I'm trying to make a bash script to pipe a new alias to .bash_aliases and then source .bashrc:

#!/bin/sh
FIRST=$1
SECOND=${2:-cd `pwd`}

if [ -z $1 ]
then
    cat ~/.bash_aliases # no arg, show aliases
else
    echo alias $FIRST="'$SECOND'" >> ~/.bash_aliases
    . /home/andreas/.bashrc
fi

The . /home/andreas/.bashrc . /home/andreas/.bashrc part doesn't work.

Following this I've tried running the script this way source . ./myscript . ./myscript .

And following this I've tried adding PS1='foobar' to the script before the . /home/andreas/.bashrc . /home/andreas/.bashrc line.

Neither works.

Answer 1

When you say "doesn't work", I assume you mean that it doesn't actually put the alias in your interactive shell. That's because this script runs in a subshell. When you source .bashrc, it installs the aliases in the subshell. Then the subshell exits, and you return to your interactive shell. There is no way to modify the environment of a parent shell from a subshell.

That said, if this code ran from a function in your parent shell, instead of in a subshell, you'd be all set. Put this function in your .bashrc

function addalias
{
    FIRST="$1"
    shift
    SECOND="$@"

    if [ "${FIRST}" == "" ]
    then
        cat ~/.bash_aliases
    else
        echo alias "$FIRST"="$SECOND" >> ~/.bash_aliases
        alias "$FIRST"="$SECOND"
    fi
}

Answer 2

That's because you are running this script in a separate shell process. The . command does work, but then the script exits and your current shell has not been altered at all.

Put this script into a function in your ~/.bash_aliases file. That way your current shell will be updated.