如何将参数传递给 RESTfull webservice 中的 GET 方法

Question

我必须将UserName和password作为参数传递给GET方法进行验证。处理后我需要得到响应。那么我如何将值传递给RESTful webservice GET方法？

Answer 1

Arguments are generally passed in a GET request as URL parameters. Without knowing what you've tried or where you're struggling, I can't really provide much more of an answer than that.

--UPDATE--

Try this: http://www.mkyong.com/webservices/jax-rs/jax-rs-queryparam-example/

Answer 2

To pass parameters in HTTP GET you should use a ? delimiter. Such as

https://mywebsite.com/user/login?username=bob&password=123
https://mywebsite.com/user/login?paramname1=value1&paramname2=value2

Make sure to always use https with any sensitive data. You may also need to escape/encode both username and password to allow extended ASCII. If you need to support UNICODE you should consider using a POST request.

Answer 3

You can do the following for Login validation,

// Create a new HttpClient and Post Header
            String downloadedString= null;

            HttpClient httpclient = new DefaultHttpClient();


            //for registerhttps://te
            HttpPost httppost = new HttpPost("YOUR LOGIN URL");
            //add data
            try{
                List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
                nameValuePairs.add(new BasicNameValuePair("username", UserName_Edit.getText().toString()));
                nameValuePairs.add(new BasicNameValuePair("password", userPassword_Edit.getText().toString()));

                //add data
                httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

                // Execute HTTP Post Request
                HttpResponse response = httpclient.execute(httppost);

                InputStream in = response.getEntity().getContent();
                StringBuilder stringbuilder = new StringBuilder();
                BufferedReader bfrd = new BufferedReader(new InputStreamReader(in),1024);
                String line;
                while((line = bfrd.readLine()) != null)
                    stringbuilder.append(line);

                downloadedString = stringbuilder.toString();

            } catch (ClientProtocolException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            }
            System.out.println("downloadedString:in login:::"+downloadedString);

Use AsyncTask for your authentication and write the above method in the doInBackground() .

EDIT

You can follow below tutorials also,

http://sarangasl.blogspot.in/2011/06/android-login-screen-using-httpclient.html

http://www.androidhive.info/2012/01/android-login-and-registration-with-php-mysql-and-sqlite/

Hope it helps.

Answer 4

I think, you should use POST method if you want to do something with user name and password. because when you use GET method, the password would be visible on the URI,

https://samplesite.com/page/login?username=John&password=123
https://sampleste.com/page/login?name1=value1&name2=value2

Instead, you could use POST method to send user name and password values and in that case the URI would like below

https://samplesite.com/page/login

And the values will be sent as,

POST /page/login.asp HTTP/1.1
Host: samplesite.com
name1=value1&name2=value2

And you get below advantages on POST Method for secured transaction with server.

• It never cached
• Requests will remain in the browser history
• Requests cannot be bookmarked
• Requests have no restrictions on data length

Answer 5

Hi you can pass arguments to GET method in RESTfull like :

 http://yoururl/<arg1>/<arg2>

eg.

 http://yoururl/abc/123