[英]Regex matching file names
I have some template for file names like: 我有一些文件名模板,如:
$subject-id$-subject-info.xml
$sampleId$-$subjectId$-sample-info.txt
$subjectId$-$sampleId$-sample-info.txt
$subjectId$-$sampleId$-image-$type$.png
$sampleId$-$subjectId$-image-$type$.jpg
image-$sampleId$-$subjectId$-$type$.jpg
order of type
, sample-id
, subject-id
not constantly set. type
顺序, sample-id
, subject-id
不经常设置。
I need to select files which matching this templates. 我需要选择与此模板匹配的文件。
for example: 例如:
for first template maching string: 对于第一个模板加工字符串:
"123A-subject-info.xml" ($subject-id$ is string)
for second: 第二个:
"2014-04-17-17-42-57-O1CD-sample-info.txt" ($sample-id$ is date time type)
for last: 最后:
"image-2014-04-17-17-42-57-01CD-mini.jpg" ($type$ is another string)
How can i do it with regex ? 我怎么能用正则表达式做到这一点? I try to parsing this strings using split method, but i need to rewrite this method constantly if the template was changed.
我尝试使用split方法解析此字符串,但如果模板已更改,我需要不断重写此方法。
For example if the file is in php then it would be /^\\S[a-zA-Z]+.(php)$/ But you can replace php with your preferred extension. 例如,如果文件是在php中,那么它将是/ ^\\S[a-zA-Z]+ .(php) $/但是你可以用你喜欢的扩展名替换php。
try using http://regex101.com/ to check your regular expression 尝试使用http://regex101.com/检查您的正则表达式
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