使用php从包含2个指定字母的文本文件中查找单词

Question

I have a list of words in a text file say:

Adam
Tony
Bob
Chris
Tommy

And I have 2 letters say t & y

I need to find the words in the list containing both letters. How can I do it?

Answer 1

Use file() and preg_grep() . file() loads the words into an array, and preg_grep() returns array entries that match the pattern.

$words = file('file.txt', FILE_IGNORE_NEW_LINES);
$letters = array('t','y');
$result = preg_grep('/[ty]/', $words);

Output:

Array
(
    [1] => Tony
    [4] => Tommy
)

Demo

Answer 2

You can do this way..

<?php
$arr = file('names.txt');
foreach($arr as $v)
{
    if(strpos($v,'t')!==false && strpos($v,'y')!==false)
    {
        echo $v;
    }
}

Explanation :

Using file() the names are grabbed from the textfile into an array. Next , you do a foreach by cycling through the names one by one. Now you check whether t or y exists in the name and when found , you print the name of the person.

Using an array_map()

array_map(function ($v){ echo (stripos($v,'t')!==false && stripos($v,'y')!==false) ? $v :'';},file('new.txt'));

---

EDIT :

what about when there are 2 letters that are the same though and I want the words that contain that letter twice..??

<?php
$names=array('jimmy','jacky','monty','jammie');
$v='m'; //<-- Lets's search for twice of m occurence

foreach($names as $v1)
{
 $arr=array_count_values(str_split($v1));
  if($arr[$v]==2)
   {
    echo $v1."\n";
   }
}

Explanation :

As you can see jimmy and jammie are returned as output as we are searching for the m letter and they have twice of the occurrence and thus we print them up , whereas jacky and monty are ignored.

OUTPUT:

jimmy
jammie

Demo