Python：如何让python从其文件夹中打开文件？
[英]Python: How do I get python to open files out of it's folder?
问题描述
I made a program to open files windows can't but I have to put the file everywhere I want to use it.
我制作了一个程序来打开windows不能打开的文件，但我必须把文件放在我想使用它的任何地方。 How can I just give it a path to use to find the file to read?我怎样才能给它一个路径来查找要读取的文件？
Basically how would I open a file out of a program's folder?基本上我将如何从程序文件夹中打开文件？ I would think that it would be... file = open('C://Users/Name/Python33/file','r') But that isn't working.我认为它会是... file = open('C://Users/Name/Python33/file','r')但这不起作用。 Could someone give me example code?有人可以给我示例代码吗？
2 个解决方案
解决方案1
0 已采纳 2014-04-18 16:15:01
Use command line arguments:使用命令行参数：
sys.argv[...] sys.argv[...]
解决方案2
0 2014-04-18 16:20:54
You can do this either through command line arguments, as suggested by @qarma, or any other kind of I/O (taking raw_input , for instance).您可以通过@qarma 建议的命令行参数或任何其他类型的 I/O（例如，使用raw_input ）来执行此操作。 If you're unfamiliar with accessing files by paths in Python, you may find os.path useful.如果您不熟悉在 Python 中通过路径访问文件，您可能会发现os.path很有用。
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