[英]increment a value in for loop
I have the following code for for
loop, what I am trying to do is each time the loop runs the next $data
needs to be the previous $data * 1.025
我有以下for
循环代码,我想做的是每次循环运行时,下一个$data
必须是前一个$data * 1.025
$amount = 3150;
$age=22;
for ($x = $age; $x<= 60; $x++){
$data = $amount*1.025;
echo "amount_$x = $data<br>";
}
This gives me the following outcome, which is understood because the value of $data
never changes 这给了我以下结果,这是可以理解的,因为$data
的值永远不会改变
amount_22 = 3228.75
amount_23 = 3228.75
amount_24 = 3228.75
amount_25 = 3228.75
where as the outcome i am looking for should be something like 我正在寻找的结果应该像什么
amount_22 = 3228.75
amount_23 = 3309.47
amount_24 = 3392.20
amount_25 = 3477.01
I will appreciate any help in how to get the next value of $data * 1.025
我将不胜感激如何获取$data * 1.025
的下一个值
$amount
doesn't change in your loop, so $amount*1.025;
$amount
不会在循环中更改,因此$amount*1.025;
doesn't change either. 也不改变。 Try $data = $data*1.025;
尝试$data = $data*1.025;
. 。 Note you'll need to initialize $data = $amount;
注意,您需要初始化$data = $amount;
. 。
You are changing $data
based on the same variable $amount
. 您正在基于相同的变量$amount
更改$data
。 Amount does not change in the loop, so the result is the same. 循环中的金额没有变化,因此结果是相同的。
Try this: 尝试这个:
$amount = 3150;
$age = 22;
for ($x = $age; $x <= 60; $x++){
$amount = $amount*1.025;
echo "amount_$x = $amount<br>";
}
Try changing the code to this: 尝试将代码更改为此:
$amount = $amount*1.025;
echo "amount_$x = $amount<br>";
This will increment the amount
each time, and changes will be retained since amount
is declared outside the loop. 每次都会增加amount
,并且由于amount
是在循环外部声明的,因此更改将保留。
Update $amount
with each loop. 每次循环更新$amount
。
Eg 例如
$amount = 3150;
$age=22;
for ($x = $age; $x<= 60; $x++){
$amount = $amount*1.025;
echo "amount_$x = $amount<br>";
}
You said the new data has to be the previous data * 1.025, but you're multiplying $amount
instead of $data
. 您说新数据必须是先前的数据* 1.025,但是您要乘以$amount
而不是$data
。
$data = 3150;
$age=22;
for ($x = $age; $x<= 60; $x++){
$data = $data*1.025;
echo "amount_$x = $data<br>";
}
A sweet solution is to assign a variable of the product of $amount and 1.025 for iteration so: 一个不错的解决方案是为变量分配$ amount和1.025乘积的变量,以便:
<?php
$amount = 3150;
$age=22;
for ($x = $age; $x<= 60; $x++){
$amount = $amount * 1.025;
echo "amount_$x = $amount<br>";
}
?>
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