PHP 显示来自 MySQL 数据库的数据

Question

I wanted to display a page content with PHP and MySQL. But i don't know how to select and display data from PHP.

$name = $_GET['title'];
$query = "SELECT * FROM pages WHERE name = $name";
$result = mysql_query("$query");

But i don't know how to display data. I want to get the string value from content in sql table row where name = $name and display it.

If you can, please help me

Answer 1

You may try and include this in your code:

$name = mysqli_real_escape_string($_GET['title']);
$query = "SELECT * FROM pages WHERE name = $name";
$result = mysqli_query($link, $query);

while ($row = mysqli_fetch_array($result)){
    echo $row['content'];
}

mysqli_free_result($result);

Here I have assumed $link as the handle to connect to the database.

NB: You may consider passing the $_GET values through mysqli_real_escape_string() to avoid sql injections which may prove fatal to the database and its tables. You also need to consider the usage of mysqli_* functions because mysql_* functions are deprecated and will be discontinued.

Answer 2

You have error in your sql, change

$query = "SELECT * FROM pages WHERE name = $name";
$result = mysql_query("$query");

to

$query = "SELECT * FROM pages WHERE name = '".$name."'";  // as name is char it should be enclosed in quotes
$result = mysql_query($query);   // using quotes inside this will just display it without executing the query

You can fetch the results by this (if the result is only single record):

$row=mysql_fetch_array($result);   // fetch the result as an array with subscript as the field name

echo $row['content'];   // echo the value of the field content

If the query result contains multiple records then you have to do this inside a while loop like this:

while($row=mysql_fetch_array($result))   // fetch the result as an array with subscript as the field name
{
    echo $row['content'];   // echo the value of the field content
}

Answer 3

$query = mysql_query("SELECT * FROM table WHERE name = $name");
$result = mysql_fetch_array($query);

//you'll get value in var
$var=$result['content'];

Answer 4

you have to do like this

$name = $_GET['title'];
$query = "SELECT * FROM pages WHERE name = '".$name."'";
$result = mysql_query($query);

//get values returned from query
$row=mysql_fetch_array($result);

//display required content
echo $row['content'];

Also mysql_* function are deprecated.You have to stop using this. Start using PDO or prepared statements or mysqli_* function

Answer 5

First of all the mysql_ is deprecated, use mysqli_

<?php
$link = mysqli_connect("localhost", "my_user", "my_password", "world");

/* check connection */
if (mysqli_connect_errno()) {
    printf("Connect failed: %s\n", mysqli_connect_error());
    exit();
}

$query = "SELECT Name, CountryCode FROM City ORDER by ID LIMIT 3";
$result = mysqli_query($link, $query);

/* numeric array */
$row = mysqli_fetch_array($result, MYSQLI_NUM);
printf ("%s (%s)\n", $row[0], $row[1]);

/* associative array */
$row = mysqli_fetch_array($result, MYSQLI_ASSOC);
printf ("%s (%s)\n", $row["Name"], $row["CountryCode"]);

/* associative and numeric array */
$row = mysqli_fetch_array($result, MYSQLI_BOTH);
printf ("%s (%s)\n", $row[0], $row["CountryCode"]);

/* free result set */
mysqli_free_result($result);

/* close connection */
mysqli_close($link);
?>

Source: http://www.php.net/manual/en/mysqli-result.fetch-array.php

Answer 6

You can do this using Prepared Statements :

$query = "SELECT whatever1, whatever2 FROM pages WHERE name = ?";

$stmt = $connection->prepare($query);
$stmt->bind_param("s", $name);
$stmt->execute();
$stmt->bind_result($value_you_want, $value_you_want_as_well);
while($stmt->fetch()){
echo $value_you_want . $value_you_want_as_well;
}
$stmt->close();

Or you can do this using PDO :

$query = "SELECT whatever1, whatever2 FROM pages WHERE name = :name";

$stmt = $connection->prepare($query);
$stmt->bindParam(':name', $name, PDO::PARAM_STR, 20);
$stmt->execute();
$result = $stmt->fetchAll(PDO::FETCH_OBJ);
foreach ($result as $page) {
    echo $page->whatever1 . $page->whatever2;
}
$stmt = null; // Set to null to destroy connection