我无法使该程序正常工作。

Question

I have been asked to modify a program to read characters rather than numbers. i modified the array into a char array. changed the two "%d" to "%c" as below

void main (void) {

char a[100];
int counter;
int b;

counter = 0;

printf("please enter the length of the array:   ");
scanf("%d", &b );

while (counter != b)
{
    printf("please enter character:     ");
    scanf("%c", &a[counter]);
    counter++;
}

    a[counter] = '\0' ;
    counter = 0;

    while (a[counter] != '\0')
 {
printf("\n");
printf("%c",a[counter]);
counter++;
 }

 }

when i run this the program does this:

please enter the length of the array: (4)
please enter character: please enter character: (a)
please enter character: please enter character: (a)

a

a

---

() are used to indicate the user inputs.

would be really good if i could get some help.

Answer 1

You have to remember that scanf leaves the newline in the input buffer, so when you try to read a character it will that newline.

The solution is very simple: Tell scanf to read and discard leading whitespace, by adding a space in the format code:

scanf(" %c", &a[counter]);
/*     ^           */
/*     |           */
/* Note space here */