下拉列表选择表格，并选择其他下拉列表进行过滤

Question

I want to use 2 drop down lists on the same page, one of them to select the table from the Db and the other to filter the selected table. 我想在同一页面上使用2个下拉列表，其中一个从Db中选择表，另一个用于过滤选定的表。 I think this is very basic but I am new in PHP and SQL. 我认为这是非常基本的，但是我是PHP和SQL的新手。 I have no problem to use a submit to filter the table by group but I don't know where assign to $table variable the $_POST['tables'] value. 我没有问题使用提交按组过滤表，但是我不知道将$_POST['tables']值分配给$table变量的位置。

Here is the relevant part of my code, : 这是我的代码的相关部分：

 $table=table_name;

 if(isset($_POST['tables'])) { 

     $table=$_POST['tables'];

 }

 //filtering by group
    if(true===isset($_POST['value'])) { 
          if($_POST['value'] == 'All') { 
             // query to get all records 
              $query = "SELECT * FROM $table";   
          } else {   
            // filter groups
            $value=$_POST['value'];
            $query = "SELECT * FROM $table WHERE Grupo='$value'";   
          }
     } else {   
          // the first time the page is loaded 

          $query = "SELECT * FROM $table ORDER BY Grupo ASC";   
     }

     $sql = mysqli_query($con,$query);

Answer 1

index.php index.php

<html>
<head>
<script>
function sortResult(str)
{
  var e = document.getElementById("firstDrop");
  var str1 = e.options[e.selectedIndex].value;
  var e = document.getElementById("secondDrop");
  var str = e.options[e.selectedIndex].value;
if (str=="")
  {
  document.getElementById("result").innerHTML="";
  return;
  } 
if (window.XMLHttpRequest)
  {// code for IE7+, Firefox, Chrome, Opera, Safari
  xmlhttp=new XMLHttpRequest();
  }
else
  {// code for IE6, IE5
  xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
xmlhttp.onreadystatechange=function()
  {
  if (xmlhttp.readyState==4 && xmlhttp.status==200)
    {
    document.getElementById("result").innerHTML=xmlhttp.responseText;
    }
  }
xmlhttp.open("GET","results.php?q="+str+"&t="+str1,true);
xmlhttp.send();
}
</script>
</head>
<body>

<!--database name-->
<select name="tablename" id="firstDrop">
            <option selected='selected' value="yourdatabasename1">DB1</option>
            <option value="yourdatabasename2">DB2</option>
</select>
<!--sort by what-->
<select name="sortby" id="secondDrop">
            <option selected='selected' value="slno">slno</option>
            <option value="name">name</option>
            <option value="author">author</option>
</select>
<button id="sub" onclick="sortResult()">CLICK</button>

<br><br>
<div id="result"><b>Results will be listed here.</b></div>

</body>
</html>

results.php results.php

<?php
$q = $_GET['q'];
$t = $_GET['t'];

$con = mysqli_connect('localhost','yourusername','password','database');
if (!$con)
  {
  die('Could not connect: ' . mysqli_error($con));
  }

mysqli_select_db($con,"database");
$sql="SELECT * FROM ".$t." ORDER BY ".$q;

$result = mysqli_query($con,$sql);

echo "<table border='1'>
<tr>
<th>Name</th>
<th>Author</th>
<th>ID</th>
</tr>";

while($row = mysqli_fetch_array($result))
  {
  echo "<tr>";
  echo "<td>" .$row['name']. "</td>";
  echo "<td>" .$row['author'] ."</td>";
  echo "<td>" .$row['slno']. "</td>";
  echo "</tr>";
  }
echo "</table>";
echo $t;
mysqli_close($con);
?>

modify accordingly. 相应地修改。

Answer 2

you have a typo... 你有错字...

if(isset($_POST['tables'])) { 
    $tabla=$_POST['tables'];
}

change to 改成

if(isset($_POST['tables'])) { 
    $table=$_POST['tables'];
}

Answer 3

Correct your query syntax-- 更正您的查询语法-

$query = "SELECT * FROM $table";

to 至

$query = "SELECT * FROM '".$table."'";


$query = "SELECT * FROM $table WHERE Grupo='$value'";

to 至

$query = "SELECT * FROM '".$table."' WHERE Grupo='".$value."'";

and 和

$query = "SELECT * FROM '".$table."' ORDER BY Grupo";

to 至

$query = "SELECT * FROM '".$table."' ORDER BY Grupo";

下拉列表选择表格，并选择其他下拉列表进行过滤

问题描述

3 个解决方案

解决方案1
1 已采纳 2014-04-21 18:27:41

解决方案2
0 2014-04-21 18:21:42

解决方案3
-1 2014-04-21 17:52:13

下拉列表选择表格，并选择其他下拉列表进行过滤

问题描述

3 个解决方案

解决方案1 1 已采纳 2014-04-21 18:27:41

解决方案2 0 2014-04-21 18:21:42

解决方案3 -1 2014-04-21 17:52:13

解决方案1
1 已采纳 2014-04-21 18:27:41

解决方案2
0 2014-04-21 18:21:42

解决方案3
-1 2014-04-21 17:52:13