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在python中转换unicode字符串

[英]conversion of unicode string in python

I need to convert unicode strings in Python to other types such as unsigned and signed int 8 bits,unsigned and signed int 16 bits,unsigned and signed int 32 bits,unsigned and signed int 64 bits,double,float,string,unsigned and signed 8 bit,unsigned and signed 16 bit, unsigned and signed 32 bit,unsigned and signed 64 bit. 我需要将Python中的unicode字符串转换为其他类型,例如unsigned和signed int 8位,unsigned和signed int 16位,unsigned和signed int 32位,unsigned和signed int 64位,double,float,string,unsigned和signed 8位,无符号和带符号16位,无符号和带符号32位,无符号和带符号64位。

I need help from u people. 我需要你们的帮助。

use int() to convert the string to an integer. 使用int()将字符串转换为整数。 Python doesn't have different fixed-width integers so you'll just get one type of thing out. Python没有不同的固定宽度整数,所以你只需要输出一种类型的东西。

Then use struct to pack the integer into a fixed width: 然后使用struct将整数打包成固定宽度:

res = struct.pack("=B",i) ## uint8_t
res = struct.pack("=b",i) ## int8_t

res = struct.pack("=H",i) ## uint16_t
res = struct.pack("=h",i) ## int16_t

res = struct.pack("=I",i) ## uint32_t
res = struct.pack("=i",i) ## int32_t

res = struct.pack("=Q",i) ## uint64_t
res = struct.pack("=q",i) ## int64_t

res = struct.pack("=f",i) ## float
res = struct.pack("=d",i) ## double

struct produces a byte-string containing the number in binary. struct生成一个包含二进制数字的字节字符串。

EDIT: From the comments it sounds like you just want to convert the string (of decimal digits) into an integer. 编辑:从评论中听起来你只想将字符串(十进制数字)转换为整数。 Just use int() for that, however you won't get all the complicated overflow/underflow semantics of the specified types. 只需使用int() ,但是不会获得指定类型的所有复杂的上溢/下溢语义。 You can't reproduce that in python, at least not without writing a whole lot of code. 您无法在python中重现它,至少在没有编写大量代码的情况下也是如此。

I think if you want any more help you'll have to be more precise about what you want to achieve. 我想如果你想要更多的帮助,你必须更准确地了解你想要达到的目标。

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