删除字符串中的ASCII字符

Question

I am trying to remove the ASCII char(11) from the String. I can see the char(11) represents ' '. However, when adding this as a String "' '" it turns out to be "''".

How can I check that the actual is a ASCII character ' '?

The code is:

public static void main(String[] args) {
    StringBuilder stringBuilder = new StringBuilder("' 'The name is stack");
    int value = 11;
    char data = (char) value; // in debug mode this is ' '
}

I want to delete this ASCII char if if exists at index 0. The problem is that the string is "''" instead of "' '". How can this be achived?

I want the output to be The name is stack.

Answer 1

You could do

if (stringBuilder.charAt(0) == data) {
    stringBuilder.deleteCharAt(0);
}

Answer 2

I think the first "printable" character is the space symbol, at index 32. So drop anything below 32 and you should be fine. Should be trivial to extend to cover the whole string.

You can assign characters as int values, and they correspond like shown here .

        char[] chars = new char[4];
        chars[0] = 31; // character for unit separator
        chars[1] = 65; // A
        chars[2] = 66; // B
        chars[3] = 67; // C

        // build a string from the printable and unprintable chars
        String s = new String(chars);

        // check length and how it prints out
        System.out.println("[" + s +"]");
        System.out.println(s.length());

        // if char at index 0 < 32, drop it
        if(s.charAt(0) < 32)
          s = s.substring(1, s.length());

        // prints like previously, but length is now smaller
        System.out.println("[" + s +"]");
        System.out.println(s.length());