在std :: cin >>中不匹配'operator >>'

Question

I seem to be having a issue with trying to get input from a user into a string. I have done this successfully before. but now it is throwing up the error here.

error: no match for 'operator>>' in 'std::cin >> Pat1'

In reference to this code here.

#include <iostream>
#include <cmath>
#include <cctype>
#include <sstream>

using namespace std;

string PatConvert(string myString);

int main(){
    string Pat1[5],Pat2[5];
    cout<<"Please give the two five charter patterns";
    cin>>Pat1;//where the error occurs.
    cin>>Pat2;
    Pat1=PatConvert(Pat1);
    Pat2=PatConvert(Pat2);
    if (Pat1==Pat2){
        cout<<"The patterns match!";
        return 0;
    }else {
        cout<<"The patterns don't match!";
    }
}

string PatConvert(string myString){
    string filler[5];
    int fillerCount=1;
    for (int i=0; i<myString.length(); i++){
        for (int i2=0; i2<filler.length(); i2++){
            if (myString[i]==filler[i2])){
                break;
            }else if(myString[i]!=filler[i2]andi2==5){
                filler[fillerCount]=myString[i];
                myString[i]=fillerCount;
                return myString;
            };
        }
    }
}

I am wondering what is causing the issue as I have looked at other instances of this error and they seem to occur when new variable types are made without the code that lets them be "overloaded" I think it is.

But seeing as this is a string and that I have used "cin>>" before to get user input to a string I am out of ideas as what to do.

As a side note there is a lot more build error information (~200 lines). If it is needed I will add it but it doesn't seem related to this issue directly.

Answer 1

There is no operator>> for reading into arrays of std::string , you will either have to define your own or use a loop.

for (auto& s : Pat1)
  std::cin >> s;

Then again you may have not intended to define an array of strings in the first place, redefine your strings as string Pat1, Pat2;

Other errors include not returning a string in PatConvert , an extra bracket in if (myString[i] == filler[i2])) and this } else if (myString[i] != filler[i2]andi2 == 5) { should probably be } else if ((myString[i] != filler[i2]) && (i2 == 5)) {