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如何在Python中使用递归查找数字的增量?

[英]How can I use recursion to find increments of a number in python?

I have the following code, but it just doesn't work when I run it. 我有以下代码,但是在运行时它不起作用。 I would like it to return something like: [5,10,15,20] if the inputed value for n is 4. Any advice is very appreciated. 我希望它返回如下内容:[5,10,15,20]如果n的输入值为4。非常感谢任何建议。

def MultipleRecursive(n):
    multiples=[]
    if n==0:
        multiples.append(n)
    else:
        Total=5*MultipleRecursive(n-1)
        multiples.append(Total)
    return multiples

A trivial version is: 一个简单的版本是:

def mr(n):
    if n == 0:
        return []
    return mr(n-1) + [5*n]

You can try this: 您可以尝试以下方法:

def rek(n):
    list = []
    if n == 0:
        return list
    else:
        list = rek(n-1)
        list.append(5*n)
        return list

print rek(4)
>>> [5, 10, 15, 20]

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