[英]regex to match digit word in numbers
Here is my regex to validate the phone number. 这是我用来验证电话号码的正则表达式。 which works fine for various numbers like 1223534345
etc . 它适用于各种数字,如1223534345
等。
/(?:\((\+?\d+)?\)|(\+\d{0,3}))? ?\d{2,3}([-\.]?\d{2,3} ?){3,4}/
snippet: 片段:
foreach ($words as $word){
$arrwords = array(0=>'zero',1=>'one',2=>'two',3=>'three',4=>'four',5=>'five',6=>'six',7=>'seven',8=>'eight',9=>'nine');
preg_match_all('/[A-za-z]+/', $text, $matches);
$arr=$matches[0];
foreach($arr as $v)
{
$text= str_replace($v,array_search($v,$arrwords),$text);
}
$pattern = '/(?:\((\+?\d+)?\)|(\+\d{0,3}))? ?\d{2,3}([-\.]?\d{2,3} ?){3,4}/';
preg_match_all($pattern, $text, $matches, PREG_OFFSET_CAPTURE );
$this->pushToResultSet($matches);
}
But I want to add exploits like this: 但是我想添加这样的漏洞:
1223five34345
, it should also be considered as 1223534345
and should be filtered. 1223five34345
,也应将其视为1223534345
并应进行过滤。 Is this possible ? 这可能吗 ?
Map all those words as shown in the $arrwords
, now do a preg_match_all()
to check for all the occurrences of the words. 映射所有这些单词,如$arrwords
所示,现在执行preg_match_all()
来检查单词的所有出现情况。 Grab them in array. 抓住他们的数组。 Now loop that array and check if that value exists in the $arrwords
array , if found map the key to the string. 现在循环该数组,并检查$arrwords
数组中是否存在该值(如果找到),将键映射到字符串。
<?php
$arrwords = array(0=>'zero',1=>'one',2=>'two',3=>'three',4=>'four',5=>'five',6=>'six',7=>'seven',8=>'eight',9=>'nine');
$str='I won total five prize';
preg_match_all('/[A-za-z]+/', $str, $matches);
$arr=$matches[0];
foreach($arr as $v)
{
$v = strtolower($v); //<--- Fail safe !!
if(in_array($v,$arrwords))
{
$str = str_replace($v,array_search($v,$arrwords),$str);
}
}
echo $str; //I won total 5 prize
You can now validate this $str
with your regular expression. 现在,您可以使用正则表达式验证此$str
。
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