Bash如何格式化日期

Question

I want to grep a file with the following date format:

Thu Apr 24

At the moment I only have date +"%d %m %Y" and that's returning 24 04 2014.

How do I format to get "Thu Apr 24"?

So I need the day month and date?

Answer 1

man date将建议date +"%a %b %d"

Answer 2

You can try

date +"%a %b %d"

where

   %a     locale's abbreviated weekday name (e.g., Sun)

   %b     locale's abbreviated month name (e.g., Jan)

   %d     day of month (e.g., 01)