正则表达式：忽略以特定字符开头的匹配项

Question

I have the following RegEx:

(.+?)\1+

It is used for recognizing repeated sequences in a string. But the matches may not consist of only digits or points and also they may not start with a point or end with a digit. I tried using:

^[^\.](.+?)\1+$[\d]

But this solution is not working. For example it is not recognizing 4F.4F.4F.

Edit:

I found the solution by combining all the ideas of the answers. It is:

(?!\\.)(.+?)\\1+(?<=\\D)

Answer 1

This id what you need.

result = re.findall(r"^(?!\.)(\w+\.)(?!.\d)\1+", subject)

DEMO http://regex101.com/r/pA5bL0

Answer 2

You need to put \\D (non-digit) before $ :

^[^\.](.+?)\1+\D$

DEMO

Answer 3

I'd use Lookaheads:

(?!\.)(.+)(?<![0-9])\1+

Demo: http://regex101.com/r/iQ0aT6

Answer 4

这符合您的规格：

result = re.findall(r"([^.].*?\D)\1", subject, re.DOTALL)