使用AWK打印匹配的图案

Question

For example i have this data:

/home/test/dat1.txt
/home/test/dat2.txt
/home/test/test1/dat3.txt
/home/test/test2/dat4.txt
/home/test/test3/test4/dat5.txt

I need to print only the name and extension, that output should be:

dat1.txt
dat2.txt
dat3.txt
dat4.txt
dat5.txt

I need to use the awk command... anyone can help?

I use this regular expression: '/\\/*\\.txt/{print ???}

Answer 1

If you are going to use awk , you do not need a regex for this purpose. You can just tell awk to print the last field, using a field separator of / .

awk -F'/' '{print $NF}' Input.txt

As hd1's comment already noted, NF is the number of fields on the current input record (in this case line). Since awk starts indexing fields at $1 , $NF gives you the last field.

Answer 2

You could use this short awk

awk -F/ '$0=$NF' Input.txt

If you need empty line use

awk -F/ '{$0=$NF}1' Input.txt