Ajax调用完成后执行函数

Question

I am new to Ajax and I am attempting to use Ajax while using a for loop. After the Ajax call I am running a function that uses the variables created in the Ajax call. The function only executes two times. I think that the Ajax call may not have enough time to make the call before the loop starts over. Is there a way to confirm the Ajax call before running the function printWithAjax()? I do not want the printWithAjax() function to execute until the Ajax call is complete. Any help will be greatly appreciated.

var id;
var vname;
function ajaxCall(){
for(var q = 1; q<=10; q++){
 $.ajax({                                            
         url: 'api.php',                        
         data: 'id1='+q+'',                                                         
         dataType: 'json',
         async:false,                    
         success: function(data)          
         {   
            id = data[0];              
            vname = data[1];
         }
      });

       printWithAjax(); 

 }//end of the for statement
}//end of ajax call function

Answer 1

Try this code:

var id;
var vname;
function ajaxCall(){
for(var q = 1; q<=10; q++){
 $.ajax({                                            
     url: 'api.php',                        
     data: 'id1='+q+'',                                                         
     dataType: 'json',
     async:false,                    
     success: function(data)          
     {   
        id = data[0];              
        vname = data[1];
     },
    complete: function (data) {
      printWithAjax(); 
     }
    });

  }//end of the for statement
  }//end of ajax call function

The "complete" function executes only after the "success" of ajax. So try to call the printWithAjax() on "complete". This should work for you.

Answer 2

You can use .ajaxStop() or .ajaxComplete()

.ajaxComplete() fires after completion of each AJAX request on your page.

$( document ).ajaxComplete(function() {
  yourFunction();
});

.ajaxStop() fires after completion of all AJAX requests on your page.

$( document ).ajaxStop(function() {
  yourFunction();
});

Answer 3

Add .done() to your function

var id;
var vname;
function ajaxCall(){
for(var q = 1; q<=10; q++){
 $.ajax({                                            
         url: 'api.php',                        
         data: 'id1='+q+'',                                                         
         dataType: 'json',
         async:false,                    
         success: function(data)          
         {   
            id = data[0];              
            vname = data[1];
         }
      }).done(function(){
           printWithAjax(); 
      });



 }//end of the for statement
}//end of ajax call function

Answer 4

You should set async = false in head. Use post/get instead of ajax.

jQuery.ajaxSetup({ async: false });

    $.post({
        url: 'api.php',
        data: 'id1=' + q + '',
        dataType: 'json',
        success: function (data) {

            id = data[0];
            vname = data[1];

        }
    });

Answer 5

try

var id;
var vname;
function ajaxCall(){
for(var q = 1; q<=10; q++){
 $.ajax({  

 url: 'api.php',                        
 data: 'id1='+q+'',                                                         
 dataType: 'json',
 success: function(data)          
  {

    id = data[0];              
   vname = data[1];
   printWithAjax();
}
      });



}//end of the for statement
  }//end of ajax call function

Answer 6

Append .done() to your ajax request.

$.ajax({
  url: "test.html",
  context: document.body
}).done(function() { //use this
  alert("DONE!");
});

See the JQuery Doc for .done()