[英]How do I store (adjoint) functors in a pair?
I have two functors which are adjoint ie they occur in pairs If one is doX()
, the other will be undoX()
.我有两个伴随的函子,即它们成对出现如果一个是doX()
,另一个将是undoX()
。
They have been declared like so:他们是这样声明的:
template< typename T >
struct doSomething{
void operator()( T &x ) const {
.....
.....
.....
}
};
template< typename T >
struct undoSomething{
void operator()( T &x ) const {
.....
.....
.....
}
};
These are used by a class on it's member variables.这些由类在其成员变量上使用。
How can I store them in an std::pair which I can pass in the class's constructor?我如何将它们存储在一个 std::pair 中,我可以在类的构造函数中传递它?
PS A solution without C++11 or boost would be appreciated. PS 没有 C++11 或 boost 的解决方案将不胜感激。 But I'm willing to use them as a last resort但我愿意用它们作为最后的手段
Container class:容器类:
struct Container
{
typedef int DoUndoType; // This is an example, the actual type will
// have to be decided by you.
// The constructor and its argument.
Container(std::pair<doSomething<DoUndoType>,
undoSomething<DoUndoType>> const& doUndoPair) : doUndoPair(doUndoPair) {}
std::pair<doSomething<DoUndoType>,
undoSomething<DoUndoType> doUndoPair;
};
Use of Container class: Container类的使用:
// Construct an object.
Container c(std::make_pair(doSomething<Container::DoUndoType>(),
unDoSOmething<Container::DoUndoType>()));
// Use the pair.
int arg = 10;
c.doUndoPair.first(arg);
c.doUndoPair.second(arg);
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