Linux上的Sed命令仅匹配1，在Solaris上找到多个匹配项

Question

note I'm a beginner with SED.

We make use of sed-command which looks in the output of a clearcase command and obtains the names of users with a view:

<clearcase output> | sed -n "/Development streams:/,// s/[^ ]* *Views: *\([^_ ]*\)_.*/\1/p"

(Example clearcase output:

Project:              project:xx0.0_xx0000@/xxxx/xxxxx_xxxxxxxx0
Project's mastership: XXXXXXXXX@/xxxx/xxxxx_xxxxxxxx0
Project folder:       folder:XX0.0@/xxxx/xxxxx_xxxxxxxx0 (RootFolder/Xxxxxxxx/XX0.0)
Modifiable components:component:00000000000@/xxxx/xxxxxx_xxxxxxxx0
                      component:xxxxxxx_xxxxxxx@/xxxx/xxxxxx_xxxxxxxx0
                      component:xxxxxxxxxxxxxx_x@/xxxx/xxxxxx_xxxxxxxx0
                      component:xxxxx@/xxxx/xxxxxx_xxxxxxxx0
                      component:xxxxxx_xxxxxxxxxxx@/xxxx/xxxxxx_xxxxxxxx0

Integration stream:   stream:xx0.0_xx0000_integration@/xxxx/xxxxx_xxxxxxxx0 (FI: nemelis)
Integration views:    olduser_xx0.0_xx0000_int - Properties: dynamic ucmview readwrite nshareable_dos
                      nemelis_xx0.0_xx0000_int - Properties: dynamic ucmview readwrite nshareable_dos
                      otheruser_xx0.0_xx0000_int - Properties: dynamic ucmview readwrite nshareable_dos

Development streams:  stream:nemelis_xx0.0_xx0000@/xxxx/xxxxx_xxxxxxxx0 [unlocked] - No rebase or delivery is pending.
                       Views:nemelis_xx0.0_xx0000
                      stream:otheruser_xx0.0_xx0000_streamidentifier@/xxxx/xxxxx_xxxxxxxx0 [unlocked] - No rebase or delivery is pending.
                       Views:otheruser_xx0.0_xx0000_streamidentifier

)

On Solaris it will output:

nemelis

otheruser

But on (Redhat-)Linux only the first name is given.

(Note: I've looked on Stackoverflow and found comments that Sed is always greedy on Posix / Gnu and that Perl should be used (see Non greedy regex matching in sed? ). Thus I've tried to fix it with Perl, but than I ran into a forrest of problems with the p at the end, using "//", "|", missing operator before < token >, etcetera, hence my post here)

Answer 1

Not sure what you're trying to achieve by specifying the address as // . You probably imply that it should be end of file or a blank line. Use $ as the address in the former case, and /^$/ in the latter.

The following might work for you:

sed -n "/Development streams:/,$ s/[^ ]* *Views: *\([^_ ]*\)_.*/\1/p"

From the manual:

$

  This address matches the last line of the last file of input, or the last line of each file when the `-i' or `-s' options are specified.