从jquery集合中删除元素

Question

Let's say I get a set of jquery elements

var bad_elements = $('.my_elements.bad');
var all_elements = $('.my_elements);

var good_elements = ??? How can I do this ??? // $('.my_elements') - $('.my_elements.bad');

Answer 1

var good_elements = $(".my_elements:not(.bad)");

Answer 2

Just filter out the bad elements

var good = all_elements.filter(function() {
    return !$(this).is(bad_elements);
});

FIDDLE

Answer 3

Basically you can do this, I suppose:

all_elements.filter(":not(.bad)");

This filters out the bad elements.

Answer 4

Since you already have 2 jQuery object, you can use .not :

var good_elements = all_elements.not(bad_elements);

Alternatively, if you want to optimise you code, you could do :

var all_elements = $('.my_elements'),
    bad_elements = all_elements.filter('.bad'),
    good_elements = all_elements.not(bad_elements);