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ruby基于键合并哈希表数组,并按键/值对的数量对其进行排序

[英]ruby merge array of hashes based on the key and order it by number of key/value pair

I have this array of hashes: 我有这个哈希数组:

ah = [{"Date"=>"2014-03-17", "countdown 7"=>1}, {"Date"=>"2014-03-17", "voice 6"=>1},     
 {"Date"=>"2014-03-18", "voice 1"=>1}, {"Date"=>"2014-03-18", "voice 2"=>0},     
 {"Date"=>"2014-03-18", "voice 3"=>1}, {"Date"=>"2014-03-18", "voice 4"=>0},    
 {"Date"=>"2014-03-18", "voice 5"=>0}, {"Date"=>"2014-03-18", "voice 6"=>0},     
 {"Date"=>"2014-03-19", "voice 5"=>0}, {"Date"=>"2014-03-19", "voice 6"=>0},    
 {"Date"=>"2014-03-20", "countdown 5"=>1}, {"Date"=>"2014-03-20", "voice 7"=>0},     
 {"Date"=>"2014-03-20", "voice 6"=>0}]   

and i want to merge it based on the key to have : 我想根据具有的关键将其合并:

ah = [{"Date"=>"2014-03-17", "countdown 7"=>1, "voice 6"=>1},      
 {"Date"=>"2014-03-18", "voice 1"=>1, "voice 2"=>0, "voice 3"=>1, "voice 4"=>0, "voice 5"=>0, "voice 6"=>0},       
 {"Date"=>"2014-03-19", "voice 5"=>0, "voice 6"=>0},       
 {"Date"=>"2014-03-20", "countdown 5"=>1, "voice 7"=>0, "voice 6"=>0}]         

Tried : 尝试过:

ah.inject { |all, h| all.merge(h) } #no success

Any hints on how to do that? 有关如何执行此操作的任何提示?

update 更新
Would it be possible to sort it by number of key/value pair? 是否可以按键/值对的数量对其进行排序? So that the hash that have the most key/value be the first and the one that has the least key value be last? 这样,具有最大键/值的哈希值是第一个,而具有最小键值的哈希是最后一个?

Output 产量

[{"Date"=>"2014-03-18", "voice 1"=>1, "voice 2"=>0, "voice 3"=>1, "voice 4"=>0, "voice 5"=>0, "voice 6"=>0},   
 {"Date"=>"2014-03-20", "countdown 5"=>1, "voice 7"=>0, "voice 6"=>0},
 {"Date"=>"2014-03-17", "countdown 7"=>1, "voice 6"=>1},              
 {"Date"=>"2014-03-19", "voice 5"=>0, "voice 6"=>0}       
]       

** Update 2 ** **更新2 **
To sort the array of hashes by lenght of key/value pair: 按键/值对的长度对哈希数组进行排序:

ah.sort {|a, b| a.length <=> b.length}.reverse  

I'd do : 我会做 :

ah.group_by { |h| h['Date'] }.map { |_,v| v.inject(:update) }
# => [{"Date"=>"2014-03-17", "countdown 7"=>1, "voice 6"=>1},
#     {"Date"=>"2014-03-18",
#      "voice 1"=>1,
#      "voice 2"=>0,
#      "voice 3"=>1,
#      "voice 4"=>0,
#      "voice 5"=>0,
#      "voice 6"=>0},
#     {"Date"=>"2014-03-19", "voice 5"=>0, "voice 6"=>0},
#     {"Date"=>"2014-03-20", "countdown 5"=>1, "voice 7"=>0, "voice 6"=>0}]

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