AWK如何初始化要打印的多个字段的变量

Question

I'm writing a SHELL script that will call an AWK script file printing specific fields based on the options specified by the user from the .sh script

EXAMPLE

-N=field with a list of Names               ==> is the filed number 2
-A=field with a list of Addresses           ==> is the filed number 4
-P=field with a list of Prices              ==> is the field number 6
-D=field with a list of Dates               ==> is the field number 10


./SHELLSCRIPT.sh -N -A -P -D

NAMES,ADDRESSES,PRICES,DATES
NAMES,ADDRESSES,PRICES,DATES
NAMES,ADDRESSES,PRICES,DATES

EXAMPLE

./SHELLSCRIPT.sh -N -D

NAMES,DATES
NAMES,DATES
NAMES,DATES

I'm trying to initialize a variable inside AWK using the -v option passing the number of fields but I'm having some difficulties on printing it...

here is the AWK script:

#!/usr/bin/awk -f
BEGIN {
        FS="\",\"" ;
        -v test=2,4,6,10
        for (i in test)
        print $test[i];
        }

AWK script must exclude some field/s when the user doesn't specify some option/s in the shell script

Thanks in advance for your attention and support.

Answer 1

-v is an awk ARGUMENT, not a language construct. It's something you specify on the awk command line, like -F . Nevere use a shebang to invoke awk from a script as it just takes away from available functionality. Instead of what you had:

#!/usr/bin/awk -f
BEGIN {...}

you'd do this:

/usr/bin/awk '
BEGIN {...}
' "$@"

which then lets you use awk args, access shell positional parameters, exported variables, etc. as you like, eg:

/usr/bin/awk -v test='2,4,6,10' '
BEGIN {...}
' "$@"

Now, to address your actual problem you'd write:

/usr/bin/awk -F'"," -v test='2,4,6,10' '
BEGIN {
    split(test,array1,/,/)
    for (i in array1)
        array2[array1[i]]
}
{
    print "array1:"
    for (i=1; i in array1; i++) {
        print i, $(array1[i])
    }
    print "array2:"
    for (i in array2) {
        print i, $i
    }
}
' "$@"

array1 would be what you use when you do care about the order in which the fields are output, array2 would be when you don't care about the order.

Answer 2

Maybe this wil help:

awk -v bozo=12 -v brains=99 'BEGIN{print bozo,brains}' /dev/null
12 99