数组索引无法正常工作

Question

Hey guys i have tried to add the key of an array to another array's key but i didnt get the output as i expected ..My code is

<?php

$some = array('anna'=>'2','revathy'=>'baba');

$honey = array_keys($some);


$something = array();



foreach($honey as $value) {

$something[$value]=$some[$value];


echo $something[$value];

 }

?>

When i run this code it shows blank screen instead of the output ..Hope you guys can help me out ..Any help would be appreaciated..

Answer 1

This is because array_keys returns something like this:

array (size=2)
  0 => string 'anna' (length=4)
  1 => string 'revathy' (length=7)

So, what you need to do to make your script work is like this:

ps in your script you had an undefined variable $v

<?php

$some = array('anna'=>'2','revathy'=>'baba');

$honey = array_keys($some);

$something = array();

foreach($honey as $key => $value) // this is the change
{
    $something[$value] = $some[$value];

    echo $something[$value] ."<br>"; // and here
}

Outputs:

2
baba

Answer 2

foreach ($honey as $key => $value) {
    $something[$key]=$value;
}

This is the proper way of dong this :) There is absolutely no need for $honey = array_keys($some);

Answer 3

You don't need to do that to copy an array with php. The equal operator copies it unless you use the reference operator ( = &$some ).

The only thing you have to do is :

<?php

$some = array('anna'=>'2','revathy'=>'baba');
$something = $some;

?>

And to additionally print it :

echo implode(', ', array_values($something));

Answer 4

将$ v更改为$ value，对我有用

Answer 5

you can skip

$honey = array_keys($some);

just do

foreach($some as $key => $value)
{
    $something[$key] = $value;
}