将TINYINT（1）转换为字符串

Question

I want to convert a TINYINT(1) value to string. Let's say if subscription paid is equal to 1 (or true) then the outcome will be "yes" when I retrieve the value from my MySQL database to my .php file. If subscription paid = 0 (or false) the the outcome will be "no".

Is there a way to convert a TINYINT(1) value to a string containing my words of choice?

I am sorry if I am being indirect or if more information about the issue is required

Answer 1

You can use an IF :

SELECT IF(`column` = 1, 'yes', 'no') FROM `table_name`

Or:

SELECT IF(`column` = 0, 'no', 'yes') FROM `table_name`

Or you can use < or > etc. based on the data.

Answer 2

Given that MySQL does not provide any decent mechanism to prevent inserting -1 or 33 into a TINYINT column, I'd simply test against zero/non-zero:

SELECT CASE
    WHEN paid<>0 THEN 'Yes'
    WHEN paid=0 THEN 'No'
    ELSE 'Unknown'
END is_paid
FROM suscription

The question is also tagged as PHP . I think it's cleaner to use native types as much as possible:

if (is_null($row['paid']) {
    $paid = null;
}else{
    $paid = $row['paid']!=0;
}

Getting the right string when displaying should be straightforward.

Answer 3

You can do this in PHP:

$number = 1; // or 0 - basically your MySQL variable
$word = $number ? "yes" : "no";

Alternatively, do it in your MySQL query:

SELECT IF(`column_name` = 1, 'yes', 'no') FROM ...