[英]Invalid column name error while using group by
I am getting Invalid column error on acctkey column. 我在acctkey列上收到无效列错误。 Can you please tell me what am I doing wrong?
你能告诉我我在做什么错吗?
select COUNT(acctkey) as Num, case
when source_sys_cd in ('TRS','CLS') then source_sys_cd + '|'+[acct_num]
when source_sys_cd = 'Hogan CIS' and [acct_type_cd] = 'DDA' then 'DDA' + '|'+ [acct_id]
when source_sys_cd = 'Hogan CIS' and [acct_type_cd] != 'DDA' then 'TDA' +'|'+ [acct_id]
when source_sys_cd = 'CLN' then source_sys_cd + '|'+ [acct_num]+ [acct_id]
when source_sys_cd = 'RCC' then source_sys_cd + '|'+ [acct_id]
when source_sys_cd = 'ITF' then source_sys_cd + '|'+ [acct_id]+ [acct_num]
when source_sys_cd = 'SEC' then source_sys_cd + '|'+ [acct_id]
else source_sys_cd + '|'+ [acct_num]
end as acctkey
from mtb..STAGING_CUST_ACCT
group by source_sys_cd
,acct_id
,acct_num
,acctkey
,acct_type_cd
In your case, you could technically fix the problem just by removing acctkey
from the group by: 就您而言,您可以通过
acctkey
从技术上仅通过从组中删除acctkey
来解决问题:
group by source_sys_cd, acct_id, acct_num, acct_type_cd
All these columns are included in the definition of the acctkey
(if I didn't miss anything). 所有这些列都包含在
acctkey
的定义中(如果我什么都没错过的话)。 However, I doubt that is what you really want, because that is likely to produce duplicates for the acctkey
. 但是,我怀疑那是您真正想要的,因为这很可能会为
acctkey
产生重复acctkey
。
Instead, I think you want: 相反,我认为您想要:
with t as (
select t.*,
(case
when source_sys_cd in ('TRS','CLS') then source_sys_cd + '|'+[acct_num]
when source_sys_cd = 'Hogan CIS' and [acct_type_cd] = 'DDA' then 'DDA' + '|'+ [acct_id]
when source_sys_cd = 'Hogan CIS' and [acct_type_cd] != 'DDA' then 'TDA' +'|'+ [acct_id]
when source_sys_cd = 'CLN' then source_sys_cd + '|'+ [acct_num]+ [acct_id]
when source_sys_cd = 'RCC' then source_sys_cd + '|'+ [acct_id]
when source_sys_cd = 'ITF' then source_sys_cd + '|'+ [acct_id]+ [acct_num]
when source_sys_cd = 'SEC' then source_sys_cd + '|'+ [acct_id]
else source_sys_cd + '|'+ [acct_num]
end) as acctkey
from mtb..STAGING_CUST_ACCT t
)
select count(*), acctkey
from t
group by acctkey;
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