[英]Comparator of a generic class
I have a generic class : 我有一个通用类:
class Card<T extends Enum<T> & Rank> implements Comparable<Card<T>>
Rank
is java interface. Rank
是java接口。 I'm trying to make a Comparator
instance in the Card
class. 我正在尝试在Card
类中创建一个Comparator
实例。
public final static Comparator<Card> comparator = new Comparator<Card>() { ... }
The previous line has a warning. 前一行有一个警告。
Card is a raw type. 卡是原始类型。 References to generic type Card should be parameterized 泛型卡的引用应参数化
How can I declare the generic type of the Card
class ? 如何声明Card
类的通用类型?
public class Card<T extends Enum<T> & Rank> {
private final T rank;
private final Suit suit;
public Card(T rank, Suit suit)
{
this.rank = rank;
this.suit = suit;
}
public final static <T extends Enum<T> & Rank> Comparator<Card<T>> byRank()
{
return new Comparator<Card<T>>() {
@Override
public int compare(Card<T> o1, Card<T> o2)
{
int r = compareRank(o1, o2);
return r != 0 ? r : compareSuit(o1,o2);
}
};
}
public final static <T extends Enum<T> & Rank> Comparator<Card<T>> bySuit()
{
return new Comparator<Card<T>>() {
@Override
public int compare(Card<T> o1, Card<T> o2)
{
int r = compareSuit(o1,o2);
return r != 0 ? r : compareRank(o1, o2);
}
};
}
}
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